python从字母表中获取所有可能的单词

Question

Lets say I have some alphabets and numbers in my text file alphabets.txt

A B E G L I P c e f u y 2 8 9 6

I want to open this file which I can do from

f = open("/home/someuser/Documents/alphabets.txt")
for word in f.read().split():
    print(word)

But I want the random words to be printed from those alphabets.

I want words starting with 8 characters with every alphabets in it. Like permutation combination

None any word should be left from combination none should be repeated. How can I do this ??

Thanks in advance

Answer 1

Use itertools.product to get all the combinations.

>>> alphabet = "ABCDEF"
>>> words = [''.join(x) for x in itertools.product(alphabet, repeat=3)]
>>> words
['AAA', 'AAB', ... 'FFE', 'FFF']
>>> len(words)
216

For getting random words, you can random.shuffle that list and pop elements from it (no repeats), or use random.choice (with repeats)

>>> random.choice(words)
'EFA'
>>> random.shuffle(words)
>>> words.pop()
'CAD'

However, exhaustively generating all the 4,294,967,296 eight-letter-words from your alphabet will take very long. If you just need a few random samples, it would be simpler to just join 8 random letters from the alphabet.

>>> [''.join(random.choice(alphabet) for _ in range(8)) for _ in range(5)]
['28GLIGB9', 'PE8uyLue', '6c8eGByA', 'BLucIuuf', 'fEeBf9Bf']