Neo4j密码查询具有基于性别的不同关系

Question

In genealogy we use DNA to find matches. Y-DNA finds patrilineal matches. A neo4j query (where RN is a unique identifier for a person) that does this is:

MATCH (n{RN:1}) match p=n-[r:father*..22]->m return m.RN as RN,m.fullname as FullName,m.sex as Sex,m.bd as BD,m.dd as DD,length(p) as generation,case when left(m.bd,4)>'1930' and rtrim(m.dd)='' then 'Y' else 'N' end as mtDNA_Candidate, reduce(srt2 ='|', q IN nodes(p)| srt2 + q.RN + '|') AS PathOrder order by generation desc,PathOrder desc

or we use mitochondrial DNA for matrilineal matches:

`MATCH (n{RN:1}) match p=n-[r:mother*..22]->m return m.RN as RN,m.fullname as FullName,m.sex as Sex,m.bd as BD,m.dd as DD,length(p) as generation,case when left(m.bd,4)>'1930' and rtrim(m.dd)='' then 'Y' else 'N' end as mtDNA_Candidate, reduce(srt2 ='|', q IN nodes(p)| srt2 + q.RN + '|') AS PathOrder order by generation desc,PathOrder desc`

MY QUESTION is related to X-chromosome DNA. A father gives an X-chromosome to only his daughters and a mother gives one to all her children. Thus, I need a cypher query that gets all mother's but only father's when there is a daughter in the immediate more recent temporal generation. If there is a son in the later generation then I exclude the father. I have a property 'sex' in the nodes with a value of either M or F. the birth date is not always known, so it cannot be used to determine directionality

I tried this, but get an error:

`MATCH (n{RN:1}) match p=n-[r:mother*..22|father*..1]->m return m.RN as RN,m.fullname as FullName,m.sex as Sex,m.bd as BD,m.dd as DD,length(p) as generation,case when left(m.bd,4)>'1930' and rtrim(m.dd)='' then 'Y' else 'N' end as mtDNA_Candidate, reduce(srt2 ='|', q IN nodes(p)| srt2 + q.RN + '|') AS PathOrder order by generation desc,PathOrder desc`

Answer 1

[UPDATED]

The [r:mother*..22|father*..1] syntax is illegal. A relationship in a Cypher query can have at most a single variable length specification, and it must come after the relationship type(s). (Aside: note also that [:father*..1] is the same as [:father] ).

Does this query, which seems to be logically equivalent, work for you?

MATCH pf=(n { RN:1 })-[:father]->()
MATCH pm=n-[:mother*..22]->()
WITH [pf] + COLLECT(pm) AS paths
UNWIND paths AS p
WITH LENGTH(p) AS generation, NODES(p) AS ancestors
WITH generation, ancestors, LAST(ancestors) AS m
RETURN m.RN AS RN, m.fullname AS FullName, m.sex AS Sex, m.bd AS BD, m.dd AS DD, generation,
  CASE WHEN left(m.bd,4)>'1930' AND rtrim(m.dd)='' THEN 'Y' ELSE 'N' END AS mtDNA_Candidate,
  reduce(srt2 ='|', q IN ancestors | srt2 + q.RN + '|' ) AS PathOrder
ORDER BY generation DESC, PathOrder DESC;