如何使用orWhere创建动态where子句-Laravel 4

Question

how I can to write this in Eloquent and I'm uisng laravel 4?

SELECT * FROM `applicant` WHERE `id`='17' OR `id`='19'

I am thinking like this

$findIDAUTH = Auth::User()->id;
$findHrsbu = HrSbu::where('staff_id', '=', $findIDAUTH)->get();
$results = Mapplication::MApplication();
foreach($findHrsbu as $HrSbu){
    $results = $results->Where('sbu.id', '=', $HrSbu->sbu_id);
}
$results = $results->get();

if just

SELECT * FROM `applicant` WHERE `id`='17'

i'ts work but if

SELECT * FROM `applicant` WHERE `id`='17' OR `id`='19' or 'id'='20'

not working for me thanks

Answer 1

You should use whereIn with a subquery:

$results = Mapplication::whereIn('id', function ($query) {
    $query->from((new HrSbu)->getTable())
          ->select('sbu_id')
          ->where('staff_id', auth()->id());
})->get();

Answer 2

Hi Please try with this code and let me know, here is an option by laravel as you used its a similar method....

$findIDAUTH  = Auth::User()->id;
$findHrsbu   = HrSbu::where('staff_id', '=', $findIDAUTH)->get();
$results =      Mapplication::MApplication()->where(function($findHrsbu)->where(function($results) use ($findHrsbu) {
foreach($findHrsbu as $HrSbu){ 
   $results->orWhere('sbu.id', '=', $HrSbu->sbu_id);
}
})->get();

Answer 3

嗨，伙计们感谢您的回答。解决了问题，我正在使用WhereIn作为示例： $results->whereIn('sbu.id', '=', array($dataArray));