将XML节点和内部节点插入C＃中的现有XML文档

Question

Currently I have a working C# program that works as follows:

1. Accept .xls template with values (xls is manually created by user)
2. Save the values (matching fields) to the database

3. Convert and write .xls to XML. Please see below sample output:

   Existing XML Structure

Now, what I want to do is:

1. Read the existing xml (the created xml)
2. Insert another set of nodes and subnodes ( ReleaseLine and sub nodes). It must accept multiple ReleaseLine.

3. Save/create the new xml with appended nodes. Please see below output:

   This is what I'm looking for:

My existing C# program is simple but the XML nodes and hierarchy is bloody deep. I just created the C# code using new XElement method and passing values for each nodes. Then I simply use xmlDocument.Save() method to write the xml.

[Existing XML Program][3]

Answer 1

To add nodes or append content in existing xml-data I´d use Linq to XML.

 XElement xml = XElement.Load("file.xml");

        xml.Add( new XElement("uberNode",
        new XElement("childNode", content),
        new XElement("anotherChildNode", content)));
        xml.Save("file.xml");

Here are some other related solutions.

Add to specific node (with example):

Following exisiting XML-data:

`<Names>
  <Name>
    <prename>John</prename>
    <lastname>Snow</lastname>
  </Name>
  <Name>
    <prename>Harry</prename>
    <lastname>Harry</lastname>
  </Name>
</Names>`

Now I want to add an "age"-tag before the first "prename"-tag and a "family"-tag after the first "lastname"-tag.

  XElement xml = XElement.Load("file.xml");

            var childrens = xml.DescendantsAndSelf().ToArray();
            var first_prename = childrens[2];
            var first_lastname = childrens[3];
            Console.WriteLine(childrens[0]); //prints out the whole content

            first_prename.AddBeforeSelf(new XElement("age", 22));

        first_lastname.AddAfterSelf(new XElement("family", new XElement("mother", "paula"), new XElement("father", "paul")));

        xml.Save("file.xml");

Outcome:

`<Names>
  <Name>
    <age>22</age>
    <prename>John</prename>
    <lastname>Snow</lastname>
    <family>
      <mother>paula</mother>
      <father>paul</father>
    </family>
  </Name>
  <Name>
    <prename>Harry</prename>
    <lastname>Harry</lastname>
  </Name>
</Names>`

I was facing the problem and Linq gave me the easiest way to accomplish that! There are also other similar way eg here . But I tried a bit more and DescendantsAndSelf() made it easier for me to go through.

Answer 2

我找到了问题的答案，这是链接http://www.xmlplease.com/add-xml-linq。使用XPathSelectElement方法，可以找到正确的节点并附加了XElement的新块。