[英]adding a 0 char after every even number in an array C
I'm trying to create a program in C which, after every even number, will add a "0". 我正在尝试在C中创建一个程序,该程序在每个偶数之后都将添加一个“ 0”。 But I have a problem.
但是我有一个问题。 If I insert for example only even numbers (5 or more numbers) the program crashes.
例如,如果我仅插入偶数(5个或更多数字),程序将崩溃。
Below is the program I have right now. 以下是我现在拥有的程序。
I would like some indications or a code sample to point out what I did wrong and how I can fix it. 我想要一些指示或代码示例来指出我做错了什么以及如何解决。
void main()
{
int *a, i, n, m;
printf("dimensiune=");
scanf_s("%d", &n);
a = (int*)malloc(n*sizeof(int));
for (i = 0; i < n; i++)
{
printf("a[%d]=", i + 1);
scanf_s("%d", &a[i]);
}
for (i = 0; i < n; i++)
{
if (a[i] % 2 == 0)
{
n++;
a = (int*)realloc(a, n*sizeof(int));
for (m = n - 1; m > i;m--)
{
a[m + 1] = a[m];
}
a[i + 1] = 0;
i++;
}
}
printf("\n currently you have %d numbers in this string\n", n);
printf("your string \n");
for (i = 0; i < n; i++)
{
printf("a[%d]=%d\n", i + 1, a[i]);
}
}
Change: 更改:
for (m = n - 1; m > i;m--)
{
a[m + 1] = a[m];
}
to: 至:
for (m = n - 1; m > i;m--)
{
a[m] = a[m-1];
}
I've just tested it, it's working for me, should work for you. 我刚刚测试过,它对我有用,应该对您有用。
I see a problem with this loop: 我看到此循环有问题:
for (m = n - 1; m > i;m--)
{
a[m + 1] = a[m];
}
When you start the loop, n is the number of element in the loop. 启动循环时,n是循环中元素的数量。 During the first iteration, m is the index of the last element of the loop.
在第一次迭代中,m是循环最后一个元素的索引。 So,
m+1
is after the last element, creating a buffer overflow. 因此,
m+1
在最后一个元素之后,从而导致缓冲区溢出。
感谢所有评论,我解决了用int main(void)替换void main()和Shady Programmer提供的解决方案的错误。
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