正则表达式在字符串末尾的第二个“。”点字符后提取字符串

Question

I want to extract the second "file extension" of a file name so: 我想提取文件名的第二个“文件扩展名”，以便：

/Users/path/my-path/super.lol.wtf/main.config.js

What I need is: 我需要的是：

.config.js

What would be totally awesome if I got an array with 2 strings in return: 如果我得到一个包含2个字符串的数组，那将是多么令人敬畏：

var output = ['main', '.config.js'];

What I have tried: 我尝试过的：

^(\d+\.\d+\.)

But that ain't working. 但这不起作用。

Thanks 谢谢

Answer 1

You could use the following: 您可以使用以下内容：

([^\/.\s]+)(\.[^\/\s]+)$

Example Here 这里的例子

([^\\/.\\s]+) - Capturing group excluding the characters / and . ([^\\/.\\s]+) - 捕获除字符/和之外的组. literally as well as any white space character(s) one or more times. 字面上以及任何空格字符一次或多次。
(\\.[^\\/\\s]+) - Similar to the expression above; (\\.[^\\/\\s]+) - 与上面的表达式相似; capturing group starting with the . 捕获组开始于. character literally; 字面上的字面; excluding the characters / and . 排除字符/和. literally as well as any white space character(s) one or more times. 字面上以及任何空格字符一次或多次。
$ - End of a line $ - 结束

Alternatively, you could also use the following: 或者，您也可以使用以下内容：

(?:.*\/|^)([^\/.\s]+)(\.[^\/\s]+)$

Example Here 这里的例子

(?:.*\\/|^) - Same as the expression above, except this will narrow the match down to reduce the number of steps. (?:.*\\/|^) - 与上面的表达式相同，但这会缩小匹配范围以减少步数。 It's a non-capturing group that will either match the beginning of the line or at the / character. 它是一个非捕获组，它将匹配行的开头或/字符。

The first expression is shorter, but the second one has better performance. 第一个表达式更短，但第二个表达式具有更好的性能。

Both expressions would match the following: 两个表达式都匹配以下内容：

['main', '.config.js']

In each of the following: 在以下各项中：

/Users/path/my-path/some.other.ext/main.config.js
some.other.ext/main.config.js
main.config.js

Answer 2

Here is what you need: 这是你需要的：

(?:\/?(?:.*?\/)*)([^.]+)*\.([^.]+\.[^.]+)$

Check Here 检查一下