使用Swift 2.0将Tableview单元格图像转移到另一个视图

Question

how to transfer tableview cell image to detail view for example i want to display the cell image in another view controller when ever user will click on cell

I have searched but not got the prefect answer...

thank you..

here is my code

Source viewController

var tweakImage: UIImage! //here I have stored the cell Image
override func prepareForSegue….{

detailVC.tweakDetailImage = tweakImage // here i am sending it to another view

}

Destination view controller

@IBOutlet weak var tweakImageView: UIImageView! // image view in destination view controller where i have to set the image

view didLoad{
tweakImageView.image = tweakDetailImage
}

Answer 1

Here is how you can do it in prepareForSegue method

    override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
        var row = tblViewTest.indexPathForSelectedRow()?.row
        //Fetch object/value for the row selected from array or dictionary
        // let say "objectAtIndex"

        var newViewController = segue.destinationViewController
        newViewController.objectSelected = objectAtIndex
    }

Make sure to make an object with name objectSelected in second view controller

        if segue.identifier == "ImageScene" {

            var row = tblViewTest.indexPathForSelectedRow()?.row
            var imageName: String = "\(row!).jpg"   //Unwrapping forcefully
            var newViewController = segue.destinationViewController as! ImageViewController
            newViewController.imageSelected = UIImage(named: imageName)
        }

Unwrapping is done forcefully for imageName as I am sure that row would have a value as I have performed the segue on UITableView's didSelectRowAtIndex method, now I can successfully see the image on my second view controller

Answer 2

You need to pass your datasource object to your detailController. There must be some data source using which you are setting image on cell. Pass it to your detail controller instance when didSelectRowAtIndexPath is being tapped.