Python二进制到一元函数

Question

Following this thread about iterating through a sequence of operators , I want also to take care of unary operators in the same sequence. I used a lambda function to get rid of the second argument but are there special purpose tools/libraries for that in Python?

a, b = 5, 7
for op in [('+', operator.add), ('-', lambda x, y: operator.neg(x))]:
    print("{} {} {} = {}".format(a, op[0], b, op[1](a, b)))

Answer 1

Just separate the processing of binary and unary operators.

a, b = 5, 7
# binary ops
for op in [('+', operator.add), ('-', operator.sub]:
    print("{} {} {} = {}".format(a, op[0], b, op[1](a, b)))

#unary ops
for op in [('-', operator.neg]:
    print("{} {} = {}".format(op[0], a, op[1](a)))