iOS9：canOpenURL 为 WhatApp 的 url 方案返回 false

Question

In my current project I need to share text on whatsapp from iOS app.

Here is my code to share text on whatsapp:

NSURL *whatsappURL = [NSURL URLWithString:@"whatsapp://send?text=Hello%2C%20World!"];
if ([[UIApplication sharedApplication] canOpenURL: whatsappURL]) {
    [[UIApplication sharedApplication] openURL: whatsappURL];
}

but canOpenURL always returning false in iOS9.

Is there any iOS9 privacy policy? Can anyone help me out?

Answer 1

In iOS 9 you must whitelist any URL schemes your App wants to query in Info.plist under the LSApplicationQueriesSchemes key (an array of strings):

For example:

So in your case, instead of fb and twitter you will have to specify whatsapp .

Note that this mechanism only applies to canOpenURL and not openURL. You do not need to have a scheme listed in Info.plist to be able to open it with openURL. Hope that helps.

Answer 2

In addition to @z22's answer if you need to add it textually (eg with Xamarin) then it looks like this:

    <dict>
        ... 

        <key>LSApplicationQueriesSchemes</key>
        <array>
            <string>whatsapp</string>
        </array>
    </dict>

Answer 3

Step:1 Add LSApplicationQueriesSchemes in Info.plist

Step:2 Add whatsapp in items

Answer 4

For me the issue was because I was using URL types instead of LSApplicationQueriesSchemes

and it work only for LSApplicationQueriesSchemes

This will not work

This will work