使用向量，距离和图表JAVA

Question

I am working with vectors in graphs. The first part of the program generates a random position point of a vector on the graph. Next, I want the program to generate another random position point of a vector on the graph. How do I generate the second position vector, keeping in mind that the distance between both position vectors has to be 1?

Answer 1

1. Randomize an angle x between 0 and 360 (or between 0 and 2*PI if you use radians).
2. Add cos(x) to the x-value of the first random position point
3. Add sin(x) to the y-value of the first random position point
4. Profit :)

Why? Geometry. All the points on the circle (cos(x), sin(x)) are always 1 unit length away from its center.