如何在不使用任何基本功能的情况下拆分字符数组

Question

I have this function: int split(char* str, char s) , so how to split the str without using strtok() or other functions?

Eg: str = "1,2,3,4,5", s = ','

After split(str, s) , output will be:

1
2
3
4
5

Sorry guys, the int return -1 if str == NULL and return 1 if str != NULL.

Answer 1

How about this? I'm not sure what the int return type means in the function so I made it the count of splits.

#include <stdio.h>
int split(char* str, char s) {
    int count = 0;
    while (*str) {
        if (s == *str) {
            putchar('\n');
            count++;
        } else {
            putchar(*str);
        }
        str++;
    }
    return count;
}

Answer 2

I didn't write code for years, but that should do?

while (*str) // as long as there are more chars coming...
{
  if (*str == s) printf('\n');  // if it is a separator, print newline
  else printf('%c',*str);       // else print the char
  str++;     // next char
}

Answer 3

string split(const char* str, char s) {
    std::string result = str;
    std::replace(result.begin(), result.end(), s, '\n');
    result.push_back('\n'); // if you want a trailing newline
    return result;
}

Answer 4

Another approach...

#include <iostream>
using namespace std;

void split(char* str, char s){
    while(*str){
        if(*str==s){
            cout << endl;
        }else{
            cout << *str;
        }
        str++;
    }
    cout << endl;
}

int main(){

   split((char*)"herp,derp",',');
}

Answer 5

and another one with iterator

#include <iostream>
using namespace std;



int main() {
    string s="1,2,3,4,5";
    char   cl=',';
    for(string::iterator it=s.begin();it!=s.end();++it) 
      if (*it == cl) 
        cout << endl; 
      else cout << *it;

    return 0;
}

http://ideone.com/RPrls7