如何从typename中删除顶级指针？

Question

For example if I have:

typedef int (*pFuncType)(int a, char b);

And I want for ease to declare a function of the type which 'pFuncType' is pointer to. Something like this:

(*pFuncType) funcDeclr;

Is this even possible?

Answer 1

Is this even possible?

This is not possible. The declaration

typedef int * intptr;  

means intptr is of new type. A new variable of type intptr can be defined as

intptr p;    // Same as int * p;  

Using intptr it is not possible to declare a variable of type int . Doing

(*inptr) i; 

is equivalent to

(*(int *)) i;

which is a wrong syntax.
The same hold true with pFuncType .

Also note that the rule of declaration is that declation specifier must comes before the declarators . * comes in declarators, therefore it can't come before any declaration specifier . Look at the grammar ¹

declaration
    declaration-specifiers ;
    declaration-specifiers init-declarator-list ;   

declaration-specifiers
    storage-class-specifier
    type-specifier
    type-qualifier
    storage-class-specifier declaration-specifiers
    type-specifier          declaration-specifiers
    type-qualifier          declaration-specifiers

init-declarator-list
    init-declarator
    init-declarator-list , init-declarator

init-declarator
    declarator
    declarator = initializer   

......
......

declarator
    direct-declarator
    pointer direct-declarator

direct-declarator
    identifier
    ( declarator )
    direct-declarator [ ]
    direct-declarator [ constant-expression ]
    direct-declarator ( )
    direct-declarator ( parameter-type-list )
    direct-declarator ( identifier-list )

pointer
     *
     * pointer
     * type-qualifier-list
     * type-qualifier-list pointer  

---

_{1 The grammar can be found in C11 standard under the section §6.7 and §6.7.6}

Answer 2

No. You can declare a non-pointer type, though:

typedef int (funcType)(int a, char b);

funcType f;

int f(int a, char b) {
    return a;
}