[英]Update rows selected by join in Oracle database
I have the following query, in which I try to put everything so that I only need to execute the query once for optimization ( oracle 12c DBMS ). 我有以下查询,在其中尝试放置所有内容,以便仅执行一次查询即可进行优化( oracle 12c DBMS )。
update PersonStatus s
set s.status = 4
where exists (
select 1 from PersonStatus s1
inner join Person p
on s1.id = p.id
where p.details = 'california' and s1.status = 0 and s1.age in (1,2,3,4,5)
)
Tables: 表格:
Person (id, details)
PersonStatus(id, status, age)
where id in PersonStatus references id in Person. 其中PersonStatus中的id引用了Person中的id。 Note that I simplified/renamed the tables just for demo purposes.
请注意,我只是出于演示目的简化/重命名了表。
Basically, I just want to update the rows that match the condition in where exists (....), but I didn't seem to get it. 基本上,我只想更新存在条件(....)处与条件匹配的行,但似乎没有得到。
When I execute this, it updated all the rows in the table, but what I need is to update only those rows that have age in the given list (1,2,3,4,5). 当我执行此操作时,它更新了表中的所有行,但是我只需要更新在给定列表(1,2,3,4,5)中具有年龄的那些行。 This is for Oracle 12c database.
这是针对Oracle 12c数据库的。
Any idea why the behavior is like that? 知道为什么这种行为吗? Suggestions are appreciated.
建议表示赞赏。
===== in MySQL. =====在MySQL中。 my following query works fine:
我的以下查询工作正常:
update PersonStatus s
inner join Person p on s.id = p.id
set s.status = 4;
where p.details = 'california' and s.status = 0 and s.age in (1,2,3,4,5)
I try to achieve this in Oracle 12c. 我尝试在Oracle 12c中实现这一目标。
I think the below modified query should work for you 我认为以下修改后的查询应该适合您
update PersonStatus s
set s.status = 4
where exists (select 1
from Person p
where s.id = p.id
and p.details = 'california'
)
and s.status = 0
and s.age in (1,2,3,4,5)
;
I think you just want a correlated subquery. 我认为您只需要一个相关的子查询。 In other words, you don't need
PersonStatus
in the subquery: 换句话说,您在子查询中不需要
PersonStatus
:
update PersonStatus s
set s.status = 4
where exists (select 1
from Person p
where s.id = p.id and
p.details = 'california' and
s.status = 0 and s.age in (1,2,3,4,5)
);
I am guessing that this is the logic you are looking for. 我猜这是您要寻找的逻辑。
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