android上传图片文件到PHP服务器

Question

I took this code on Internet. I can upload image file to Server successful. However, the image files cannot be opened. I think the content of the files has problem after uploading. Can anybody help me please? Thank you very much

public static void put(String targetURL, File file, String username, String password) throws Exception {

    String BOUNDRY = "==================================";
    HttpURLConnection conn = null;

    try {

        // Make a connect to the server
        URL url = new URL(targetURL);
        conn = (HttpURLConnection) url.openConnection();


        if (username != null) {
            String usernamePassword = username + ":" + password;
            //String encodedUsernamePassword = Base64.encodeBytes(usernamePassword.getBytes());
            String encodedUsernamePassword = String.valueOf(Base64.encodeBase64(usernamePassword.getBytes()));
            conn.setRequestProperty ("Authorization", "Basic " + encodedUsernamePassword);
        }


        conn.setDoOutput(true);
        conn.setDoInput(true);
        conn.setUseCaches(false);
        conn.setRequestMethod("POST");
        conn.setRequestProperty("Connection", "Keep-Alive");
        conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+BOUNDRY);


        DataOutputStream dataOS = new DataOutputStream(conn.getOutputStream());
        dataOS.writeBytes("--");
        dataOS.writeBytes(BOUNDRY);
        dataOS.writeBytes("\n");
        dataOS.writeBytes("Content-Disposition: form-data; name=\"fileToUpload\"; fileName=\"" + file.getName() +"\"" + "\n");
        dataOS.writeBytes("\n");
        dataOS.writeBytes(new String(getBytesFromFile(file)));
        dataOS.writeBytes("\n");
        dataOS.writeBytes("--");
        dataOS.writeBytes(BOUNDRY);
        dataOS.writeBytes("--");
        dataOS.writeBytes("\n");
        dataOS.flush();
        dataOS.close();




        int responseCode = conn.getResponseCode();
        if (responseCode != 200) {
            throw new Exception(String.format("Received the response code %d from the URL %s", responseCode, url));
        }

        InputStream is = conn.getInputStream();
        ByteArrayOutputStream baos = new ByteArrayOutputStream();
        byte[] bytes = new byte[4096];
        int bytesRead;
        while((bytesRead = is.read(bytes)) != -1) {
            baos.write(bytes, 0, bytesRead);
        }
        byte[] bytesReceived = baos.toByteArray();
        baos.close();

        is.close();
        String response = new String(bytesReceived);

    } finally {
        if (conn != null) {
            conn.disconnect();
        }
    }

}

public static byte[] getBytesFromFile(File file) throws IOException {
    InputStream is = new FileInputStream(file);

    // Get the size of the file
    long length = file.length();

    // You cannot create an array using a long type.
    // It needs to be an int type.
    // Before converting to an int type, check
    // to ensure that file is not larger than Integer.MAX_VALUE.
    if (length > Integer.MAX_VALUE) {
        // File is too large
    }

    // Create the byte array to hold the data
    byte[] bytes = new byte[(int)length];

    // Read in the bytes
    int offset = 0;
    int numRead = 0;
    while (offset < bytes.length
            && (numRead = is.read(bytes, offset, Math.min(bytes.length - offset, 512*1024))) >= 0) {
        offset += numRead;
    }

    // Ensure all the bytes have been read in
    if (offset < bytes.length) {
        throw new IOException("Could not completely read file "+file.getName());
    }

    // Close the input stream and return bytes
    is.close();
    return bytes;
}

And the bellow is my code in PHP:

$target = "/upload/";
$target = $target . basename( $_FILES['fileToUpload']['name']) ; 



if(move_uploaded_file($_FILES['fileToUpload']['tmp_name'], $target)) {
    echo "The file ". basename( $_FILES['fileToUpload']['name']). " has been uploaded";
    $result['login'] = true;
}else {
    $result['login']=false;
    echo "Sorry, there was a problem uploading your file.";
 }

$json = json_encode($result, JSON_PRETTY_PRINT);
print_r($json);

Answer 1

设置Content-Type时可能会出现问题，请尝试将其删除

conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+BOUNDRY);