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单击删除最接近的表单

[英]Removing the closest form on click

I have created a pizza form where the user can select a pizza and then add another pizza to the the order if they wish (by cloning the original pizza form). 我创建了一个比萨饼表单,用户可以选择一个比萨饼,然后根据需要添加另一个比萨饼(通过克隆原始的比萨饼表单)。

I would like the user to be able to remove a Pizza Form if they wish, however the removePizza function does not behave in the way I would like (ie it does not remove the closest .pizzaForm ) 我希望用户能够根据需要删除Pizza Form,但是removePizza函数不会按照我想要的方式运行(即,它不会删除最近的.pizzaForm

HTML: HTML:

<div id="1" class="pizzaForm">
    <fieldset>
        <form class="pure-form">
        <legend>Pizza</legend>
        <label><b>Pizza Type: &nbsp;</b></label>
        <select id="pizza">
            <option>Please Select:</option></option>
            <option name="margarita">Margarita</option>
            <option name="deep-pan">Deep Pan</option>
            <option name="stuffed-crust">Stuffed Crust</option>
        </select>
            <span style="float:right">
            <label><b>Pizza Size: &nbsp;</b></label>
            <select id="pizzaSize">
                <option data-price="0">Please Select:</option></option>
                <option name="e-small" data-price="4.99">Extra Small - £4.99</option>
                <option name="small" data-price="5.99">Small - £5.99</option>
                <option name="medium" data-price="6.99">Medium - £6.99</option>
                <option name="large" data-price="8.99">Large - £8.99</option>
                <option name="e-large" data-price="9.99">Extra Large - £9.99</option>
                <option name="f-size" data-price="10.99">Family Size - £10.99</option>
            </select>
            </span>
        </form>
    </fieldset>
    <fieldset style = "border-top:0px">
    <form class="pure-form">
        <legend><b>Toppings (99p Each): &nbsp;</b></legend>
        <input type="checkbox" name="onions">Onions</input>
        <input type="checkbox" name="mushrooms">Mushrooms</input>
        <input type="checkbox" name="peppers">Peppers</input>
        <input type="checkbox" name="olives">Olives</input>
        <input type="checkbox" name="garlic"> Garlic</input>
        <input type="checkbox" name="peperoni">Peperoni</input>
        <input type="checkbox" name="cheese">Pesto</input>
    </form>
    </fieldset>
    <h2 style= "float:left; margin-top:-3cm; margin-left: 8cm; border: solid black 2px; padding: 5px; width:2cm; text-align:center"> £0.00 </h2>
    <button class="removePizza" style= "float:left; margin-top:-1.5cm; margin-left: 7.8cm;">Remove Pizza</button>
    <br>
</div>
<div id="extraPizza"></div>
<center><button id="addPizza"> Add Pizza </button></center>

JavaScript: JavaScript:

var pizzaArray = new Array();

function pizza(number, pizzaCost, toppingCost) {
    this.pizzaNumber = number;
    this.pizzaCost = pizzaCost;
    this.toppingCost = toppingCost;
}

var pizzaCounter = 1;

pizzaArray.push(new pizza(pizzaCounter, 0.00, 0.00));

$("#pizza").change(function() {
    $("#pizzaSize").prop('disabled', false);
})

$(document).on("change","#pizzaSize", function() {
    var formID = $(this).closest('div').attr("id");
    for(var i = 0; i < pizzaArray.length; i++) {
        if (pizzaArray[i].pizzaNumber == formID) {
            var selectionPrice = $('option:selected', this).attr('data-price');
            var selectionInt = parseFloat(selectionPrice, 10);
            pizzaArray[i].pizzaCost = selectionInt;
            calculateCost();
        }
    }
});

$(document).on("change","input[type='checkbox']", function() {
    var checked = $(this).parent().find(":checkbox:checked").length;
    var toppingCost = (0.99 * checked);
    var formID = $(this).closest('div').attr("id");
    for(var i = 0; i < pizzaArray.length; i++) {
        if (pizzaArray[i].pizzaNumber == formID) {
            pizzaArray[i].toppingCost = toppingCost;
            calculateCost();
        }
    }
});

$( "#addPizza" ).click(function() {
    pizzaCounter++;
    pizzaArray.push(new pizza(pizzaCounter, 0.00, 0.00));
    $("#1").clone().prop("id", pizzaCounter).appendTo("#extraPizza");
    $("#"+pizzaCounter).find("input[type='checkbox']").removeAttr('checked');
    $("#"+pizzaCounter).find("h2").removeAttr('checked').html("£0.00");
});

$(".removePizza").click(function() {
    var numOfForms = $( ".pizzaForm" ).length;
    if (numOfForms > 1) {
        $(this).closest('.pizzaForm').remove();
    } else {
        alert ("Cannot delete this form!");
    }
});

Your problem is to listen for removePizza click events in future, not only for the current tags but also for future added elements. 您的问题是将来会监听removePizza单击事件,不仅监听当前标签,而且监听未来添加的元素。

So, substitute your: 因此,请替换为:

$(".removePizza").click(function() {

with: 与:

$(document).on('click', ".removePizza", function() {

So after appendTo all new pizza remove buttons will continue to works! 因此,appendTo之后,所有新的披萨移除按钮将继续起作用!

try this, 尝试这个,

$("body").on('click','.removePizza',function() {
    var numOfForms = $(this).parents('.pizzaForm').length;
    if (numOfForms >= 1) {
        $(this).parents('.pizzaForm').remove();
    } else {
        alert ("Cannot delete this form!");
    }
});

In your $("#addPizza").click() function, the form you are cloning needs to be looked up by class name instead of ID. 在$(“#addPizza”)。click()函数中,要克隆的表单需要通过类名而不是ID查找。 This is because You may have previously removed the form with that ID. 这是因为您以前可能已经删除了具有该ID的表单。 And pass TRUE inside the clone function so that events get cloned too. 并在clone函数中传递TRUE,以便事件也可以被克隆。 I have commented out your line and added the modified line below. 我已注释掉您的行,​​并在下面添加了修改后的行。 Here is a working jsFiddle: https://jsfiddle.net/ashekthegreat/qt0cgvy2/ 这是一个工作的jsFiddle: https ://jsfiddle.net/ashekthegreat/qt0cgvy2/

$("#addPizza").click(function() {
  pizzaCounter++;
  pizzaArray.push(new pizza(pizzaCounter, 0.00, 0.00));
  // $("#1").clone().prop("id", pizzaCounter).appendTo("#extraPizza");
  $(".pizzaForm:first").clone(true).prop("id", pizzaCounter).appendTo("#extraPizza");
  $("#" + pizzaCounter).find("input[type='checkbox']").removeAttr('checked');
  $("#" + pizzaCounter).find("h2").removeAttr('checked').html("£0.00");
});

Since the form is a sibling to your .removePizza button, you will need to use prevAll() to select the first/most recent previous sibling, for example: 由于表单是您的.removePizza按钮的同级对象,因此您将需要使用prevAll()选择前一个/最近的同级对象,例如:

$(this).prevAll('.pizzaForm:first').remove();

If that doesn't work, please provide a jsFiddle of your code. 如果那行不通,请提供代码的jsFiddle。

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