[英]Put every Hash Element inside of an Array Ruby
Let's say I have a Hash like this: 假设我有一个这样的哈希:
my_hash = {"a"=>{"a1"=>"b1"}, "b"=>"b", "c"=>{"c1"=>{"c2"=>"c3"}}}
And I want to convert every element inside the hash that is also a hash to be placed inside of an Array. 我想转换散列内的每个元素,这也是要放置在数组内的散列。
For example, I want the finished Hash to look like this: 例如,我希望完成的哈希看起来像这样:
{"a"=>[{"a1"=>"b1"}], "b"=>"b", "c"=>[{"c1"=>[{"c2"=>"c3"}]}]}
Here is what I've tried so far, but I need it to work recursively and I'm not quite sure how to make that work: 到目前为止,这是我尝试过的方法,但是我需要递归地进行操作,而且我不确定如何使它起作用:
my_hash.each do |k,v|
if v.class == Hash
my_hash[k] = [] << v
end
end
=> {"a"=>[{"a1"=>"b1"}], "b"=>"b", "c"=>[{"c1"=>{"c2"=>"c3"}}]}
You need to wrap your code into a method and call it recursively. 您需要将代码包装到方法中,然后递归调用它。
my_hash = {"a"=>{"a1"=>"b1"}, "b"=>"b", "c"=>{"c1"=>{"c2"=>"c3"}}}
def process(hash)
hash.each do |k,v|
if v.class == Hash
hash[k] = [] << process(v)
end
end
end
p process(my_hash)
#=> {"a"=>[{"a1"=>"b1"}], "b"=>"b", "c"=>[{"c1"=>[{"c2"=>"c3"}]}]}
Recurring proc is another way around: 重复处理是另一种解决方法:
h = {"a"=>{"a1"=>"b1"}, "b"=>"b", "c"=>{"c1"=>{"c2"=>"c3"}}}
h.map(&(p = proc{|k,v| {k => v.is_a?(Hash) ? [p[*v]] : v}}))
.reduce({}, &:merge)
# => {"a"=>[{"a1"=>"b1"}], "b"=>"b", "c"=>[{"c1"=>[{"c2"=>"c3"}]}]}
It can be done with single reduce, but that way things get even more obfuscated. 可以通过一次reduce来完成,但是那样会使事情变得更加混乱。
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