[英]Java String regex replace
My string structure is following 我的字符串结构如下
characters 1-3 are uppercase alphabets including diacritics such Ň Ö Ï 1-3个字符是大写字母,包括Ň
Characters 4-7 will always be numbers. 字符4-7始终是数字。
8th is space 第八位是太空
9th is forward slash 9号是正斜线
10th space 第十空间
11th onwards are number. 11号起是数字。
String str1 = "DIW785o / 42"; // expected result "DIW7850 / 42"
String str2 = "QLR357Ï / 11"; // expected result "QLR3571 / 11"
String str3 = "UÜÈ7477 / 00"; // expected result "UÜÈ7477 / 00"
String str4 = "A / P8538 / 28"; // expected result "AÏP8538 / 28"
String str5 = "CV0875Z / 01"; // expected result "CVO8752 / 01"
String str6 = "SW / 2188 / 38"; // expected result "SWÏ2188 / 38"
I wanted replace first 3 characters such as 我想替换前3个字符,例如
replaceAll("[2]", "Z")
.replaceAll("[0]", "O")
.replaceAll("[5]", "S")
.replaceAll(" // ","Ï) // replace space forward_slash space with Ï
and position where numbers with following 以及以下数字的位置
.replaceAll("(?i)L|(?i)I", "1")
.replaceAll("(?i)o", "0")
.replaceAll("(?i)s", "5")
.replaceAll("(?i)z", "2")
I'd say its easier without regex, since you want to replace Strings, but only when they are at certain Positions: 我想说不用正则表达式会更容易,因为您要替换字符串,但仅当它们在某些位置时才可以:
Check, if /
is somwere in the first 7 chars, and replace it with Ï
: 检查时,如果
/
是somwere今年前7个字符,并将其替换为Ï
:
if(input.indexOf(" / ") < 7 ){
input = input.replaceFirst(" / ", "Ï");
}
Then all your Strings have the same length. 然后,您的所有字符串都具有相同的长度。 Cut them now into the Number/Letter Part and replace everything you want:
现在将它们切成数字/字母部分,并替换您想要的所有内容:
String letterPart = input.substring(0,3);
String numberPart= input.substring(3,7);
String rest = input.substring(7);
letterPart = letterPart.replace("0", "O");
numberPart = numberPart.replace("o", "0");
numberPart = numberPart.replace("Ï", "1");
numberPart = numberPart.replace("Z", "2");
Then put everything together again: 然后再次将所有内容放在一起:
String result = letterPart + numberPart + rest;
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