正则表达式问题

Question

I have the following data of which i would like to convert it to regular expression.

PALMKERNEL OIL Mal/Indo dlrs tonne cif Rotterdam

Dec15/Jan16 890.00

Jan16/Feb16 900.00 +10.00

My code below doesn't seem to work. Firstly how do I determine that after the 890, there could be either nothing or there could be a +10.00 or any number in that format? I tried to use ?: but sometimes it will totally ignore the month information which i am trying to capture..In this case i do not want to capture the +10.00 or any characters after the price of 890 or 900.

(PALMKERNEL OIL Mal\\b)/(Indo dlrs tonne cif Rotterdam\\b)\\s*([^\\s]+)\\s*(\\d*.?\\d*)\\s*([^\\s]+|[+\\d*.?\\d*])\\s*(\\d*.?\\d*)\\s*([^\\s]+|(?:[+\\d*.?\\d*]))

Answer 1

For the part with the dates and prices, this regular expression handles the two variants in your sample string.

Pattern pat = Pattern.compile( 
     "\\w{3}\\d{1,2}/\\w{3}\\d{1,2}" +
     "\\s*(\\d+\\.\\d\\d)(\\s+\\+\\d+\\.\\d\\d)?" );
String s1 = "Dec15/Jan16 890.00";
String s2 = "Jan16/Feb16 900.00 +10.00";
Matcher m1 = pat.matcher( s1 ); 
if( m1.matches() )
  System.out.println("m1 " + m1.group(1) + ":" + m1.group(2) );
Matcher m2 = pat.matcher( s2 ); 
if( m2.matches() )
  System.out.println("m2 " + m2.group(1) + ":" + m2.group(2) );

Output:

m1 890.00:null
m2 900.00: +10.00

There's not enough information - so I don't know about a third alternative in /+10.00/?.