Java核心如何将20个字节的字节数组转换为字符串

Question

I am getting input 20 byte . The charset used is UTF-8

when I convert it as string, I see 0000000000000000000000000000000000000000

this is correct.

But when I convert it to string, I get a empty value. I suspect charset as problem, but even after trying different charSets, I could not return the value '0'.

public String convertFromBytes(byte[] input) {
    System.out.println("BYTES ARE =="+ Hex.encodeHexString(input));
    System.out.println("VALUE IS "+ new String(input, this.charset));
    return new String(input, this.charset);
}

I tried changing charSet but not able to solve it, Any clues what I might be missing.

US-ASCII
ISO-8859-1
UTF-8 UTF-16BE UTF-16LE UTF-16

Answer 1

I have not tested the code.

AI understand, you try to convert {0x00, 0x00, 0x00...} to "000..." , but you get nothing. Since the value of '0' , as a character is not 0 but (ASCII) 48 , this wont print anything. There is a difference between dumping a hex value, and interpreting an array of hexadecimals as a string with encoding.

Try with {48, 48, 48...} , the string will be "000000.." , but the hex writeline will produce "48484848..." , or something like that.

PS: The code for '0' is 48 in base 10 .

Edit: It seems your string is not empty, just contains non-printable characters.