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json:无法解析此类json响应

[英]json: unable to parse this type of json response

I know object is like some: { and array like some: [ But when i do post request api response with, 我知道对象就像是一些: {和数组像是一些: [但是当我发布请求api响应时,

 {"code": 401, "message":"some message     text"}

What kind of json is that, I had tried alot to display the message in a textview but none worked meanwhile I'm able to display object response or array... I'm using Volley by the way, I had tried also to check 那是什么类型的json,我曾尝试过在textview中显示消息,但是在我能够显示对象响应或数组的同时却无济于事...我正在使用Volley ,我也尝试过检查

If(response.has("message"){
}else{
}

And the same check for "code" to switch it to message from string resources Thanks in advance 和相同的“代码”检查将其从字符串资源切换到消息

HERE THE FULL REQUEST: 这里是完整的请求:

    private void checkLogin(final String email, final String password) {
    // Tag used to cancel the request
    String tag_string_req = "req_login";

    pDialog.setMessage("Logging in ...");
    showDialog();

    StringRequest strReq = new StringRequest(Method.POST,
            AppConfig.URL_LOGIN, new Response.Listener<String>() {

        @Override
        public void onResponse(String response) {
            Log.d(TAG, "Login Response: " + response.toString());
            hideDialog();

            try {
                JSONObject jObj = new JSONObject(response);
                if (jObj.has("user")) {
                // user successfully logged in
                    // Create login session
                    session.setLogin(true);

                    JSONObject user = jObj.getJSONObject("user");
                    String uid = user.getString("id_user");
                    String uname = user.getString("name");
                    String uemail = user.getString("email");
                    String utoken = user.getString("user_token");
                    // Inserting row in users table
                    db.addUser(uname, uemail, uid, utoken);
                    // Launch main activity
                    Intent intent = new Intent(LoginActivity.this,
                            Activity1.class);
                    startActivity(intent);
                    finish();
                }else {
                    JSONObject jOsbj = new JSONObject(response);
                    TextView scss = (TextView) findViewById(R.id.loginerror);
                    scss.setText(jOsbj.getInt("code"));
                    String errorMsg = scss.getText().toString();
                    Toast.makeText(getApplicationContext(),
                            errorMsg, Toast.LENGTH_LONG).show();
                }


            } catch (JSONException e) {
                // JSON error
                e.printStackTrace();
                Toast.makeText(getApplicationContext(), "Json error: " + e.getMessage(), Toast.LENGTH_LONG).show();
            }

        }
    }, new Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
            Log.e(TAG, "Login Error: " + error.getMessage());
            Toast.makeText(getApplicationContext(),
                    error.getMessage(), Toast.LENGTH_LONG).show();
            hideDialog();
        }
    }) {

        @Override
        protected Map<String, String> getParams() {
            // Posting parameters to login url
            Map<String, String> params = new HashMap<String, String>();
            params.put("email", email);
            params.put("password", password);

            return params;
        }

    };

    // Adding request to request queue
    AppController.getInstance().addToRequestQueue(strReq, tag_string_req);
}

below is the JSONResponse - 以下是JSONResponse-

{
    "code": 401,
    "message": "some message text"
}

u can parse it as below - 你可以解析如下-

  1. assumming u have url response in Inputstream in then u read it in a stringBuffer buffer as below - 假设您在Inputstream中具有url响应,然后您在stringBuffer缓冲区中读取它,如下所示-

     StringBuffer buffer = new StringBuffer(); int ch = -1; while ( (ch=in.read()) != -1){ buffer.append((char) ch); } 
  2. Now simply parse the response from buffer - 现在,只需解析缓冲区的响应-

     JSONObject jObj = new JSONObject(buffer.toString()); String message = jObj.getString("message"); 
  3. U r extracted message is in string message. 您提取的消息在字符串消息中。

you used 你用过

 jsonObject jsonobject= new jsonObject("your json string");

 String Code= jsonobject.getString(code);

 String message= jsonobject.getString(message);

JSON STRING: JSON STRING:

{
      "code": 401,
      "message": "some message text"
    }

Now create a seprate class for response: 现在创建一个单独的类进行响应:

 public class ResponseDTO{
   int code;
   String message;
    }

Now if you are using android studio add following to gradle or if you are using Eclipse you can find jar on link: http://www.java2s.com/Code/Jar/g/Downloadgson222jar.htm 现在,如果您使用的是android studio,请在gradle中添加以下内容;如果您使用的是Eclipse,则可以在链接上找到jar: http//www.java2s.com/Code/Jar/g/Downloadgson222jar.htm

compile 'com.google.code.gson:gson:2.3'

After that use the following code to parse json string you already have: 之后,使用以下代码解析您已经拥有的json字符串:

String json = "the json you've recieved from server";
        //ASSUMSE YOUR JSON IS NOT NULL
        ResponseDTO response = new GsonBuilder().create().toJson(json.toString, ResponseDTO.class);
        if (response != null) {
            if (response.message.length() > 0 && response.message != null) {
                //DO WHATEVER YOU WANT}
                else{
                    //DO WHATEVER YOU WANT
                }
            }
        }

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