如何在EntityFramework中获得不同的行？

Question

How I can get to distinct row from a table using entity-framework.

Like i want to get, 2 distinct row where name is unique:

1| 04-DEC-15|   01-JAN-01   |4  |1  |10000.0    |0.0    |ship   |None   |LP_Joc1_B1 |01-JAN-01| 0

6| 28-DEC-15 |  01-JAN-01   |4  |1  |30000.0    |0.0    |ship   |None   |LP_Joc1_B2 |01-JAN-01| 0

Answer 1

//distinct based on a specific property (in this case Name)
List<Objects> listObjects = (from obj in db.Objects                             
                                select obj).GroupBy(n => new {n.Name})
                                           .Select(g => g.FirstOrDefault())
                                           .ToList();