如何对包含NSDates的数组进行排序

Question

Can you help me on sorting (ascending order) the array contains NSDate .

NSMutableArray *tempArray = [[NSMutableArray alloc]init];

[tempArray addObject: NSDate1];
[tempArray addObject: NSDate2];
[tempArray addObject: NSDate3];
[tempArray addObject: NSDate4];

Answer 1

由于NSDate响应compare ，并且默认排序顺序是递增的，因此最简单的方法是

[tempArray sortUsingSelector:@selector(compare:)];

Answer 2

Use below code:

  [your array sortUsingComparator:
  ^NSComparisonResult(id obj1, id obj2){

         obj1 *o1 = (obj1*)obj1;
         obj2 *o2 = (obj2*)obj2;
         if (o1.personAge > 02.personAge) {
            return (NSComparisonResult)NSOrderedDescending;
        }


        return (NSComparisonResult)NSOrderedSame;
}

];

Answer 3

NSSortDescriptor *dateSortDescriptor = [NSSortDescriptor sortDescriptorWithKey:@"self.dueDate" ascending:YES comparator:^NSComparisonResult(id obj1, id obj2) {

    NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
    [dateFormat setDateFormat:@"dd/MM/yyyy"];
    NSDate *date1 = [dateFormat dateFromString:obj1];
    NSDate *date2 = [dateFormat dateFromString:obj2];

    return [date1 compare:date2];
}];

Answer 4

Best way to do this,use sort descriptor.

 NSSortDescriptor *dateSortDescriptor = [NSSortDescriptor sortDescriptorWithKey:@"self.dueDate" ascending:YES comparator:^NSComparisonResult(NSDate *dateObject1, NSDate *dateObject2) {

return [dateObject1 compare:dateObject2];
}];

Answer 5

[array1 sortUsingComparator: (NSComparator)^(NSString *key1, NSString *key2)
 {        
     return [key2 compare: key1];
 }
 ];

If you want array in ascending or descending order just change

compare

return [key1 compare: key2];