如何将php变量传递给同一页面中的其他表单？

Question

I have two forms in the same php page. I have to save the values in the first form and after is saved in the database, I can be able to use those values in the next form.

PHP code of the first form:

<?php
    include 'config.php';
    if(isset($_POST['documentRequest']))
    {
        $date = $_POST['reqDate'];
        $name = $_POST['name'];

        $insertSql = mysqli_query($conn, "INSERT INTO documentrequest(Person_idPerson, docrequest_date) VALUES ('$name', '$date');");

        //$sql = "INSERT into requestitem (DocumentRequest_idDocumentRequest, Document_idDocument) VALUE ((SELECT idDocumentRequest FROM documentrequest WHERE Person_idPerson = 6), 2)";

        header("Refresh: 2; url=doc_request.php");
        mysqli_close($conn);

    }
?>

Here is my first form:

<form class="form-horizontal form-label-left" name = "documentRequest" enctype="multipart/form-data" role="form" method="post" novalidate>

    <div class = "first">
    <div class="item form-group">
        <label class="control-label col-md-3 col-sm-3 col-xs-12">ID <span class="required">*</span></label>
        <div class="col-md-6 col-sm-6 col-xs-12">
            <input id="name" class="form-control col-md-7 col-xs-12" placeholder ="Type in ID number " name="name" required="required" type="number">
        </div>
    </div>

    <div class="ln_solid"></div>
    <div class="form-group">
        <div class="col-md-6 col-md-offset-3">
            <button id="requestDiv" type="submit" class="btn btn-success" name="documentRequest" >Proceed</button>
            <button type="submit" class="btn btn-primary">Cancel</button>
        </div>
    </div>
    </div>
</form>

Second form (this is inside another div):

<form class="form-horizontal form-label-left" name = "documentRequest" enctype="multipart/form-data" role="form" method="post" novalidate>
    <div class = "second">
        <div class="item form-group">
            <label class="control-label col-md-3 col-sm-3 col-xs-12"> Document Request(s)  <span class="required">*</span></label>
        <div class="col-md-6 col-sm-6 col-xs-12">
            <div class = "clearfix"></div>
            <p>Minimum of 1:<p>
            <input type="checkbox" name="docs[]" id="doc1" value="Certificate of Residency" /> Certificate of Residency
            <br/>
            <div class = "col-xs-3">
    <input name="d1" class="form-control col-md-7 col-xs-12" required="required" type="number">
                </div>
    <div class = "clearfix"></div>

    <input type="checkbox" name="docs[]" id="doc2" value="Barangay Clearance"  /> Barangay Clearance                                                    
    <br />
    <div class = "col-xs-3">
    <input name="d2" class="form-control col-md-7 col-xs-12" required="required" type="number">
    </div>


    <input id="a" class="form-control col-md-7 col-xs-12" name="a" value = "<?php echo isset($_POST['name'])? $_POST['name'] : "";?>" required="required" type="text">
    </div>
    </div>
    <div class="ln_solid"></div>
    <div class="form-group">
        <div class="col-md-6 col-md-offset-3">
            <button id="requestDiv" type="submit" class="btn btn-success" name="documentRequest" >Proceed</button>
            <button type="submit" class="btn btn-primary">Cancel</button>
    </div>
    </div>
</form>

Basically, I need to use the value of ID in the next form so it knows which ID it belongs to . The next form is basically about the user's requests (a series of checkboxes). How can I do that? Please help me. Thank you.

Answer 1

I'm pretty sure that when you call header("Refresh: 2; url=doc_request.php"); you are refreshing the page and losing the submitted form data.

---

If you remove that from your logic this would work:

In your second form, where you need the value, do this:

<input id="name2" class="form-control col-md-7 col-xs-12"  name="other-name" required="required" type="number" value="<?php echo isset($_POST['name']) ? $_POST['name'] : '';?>">

This will automatically add the posted value to the second form's input element value if the posted value exists

Note that checking isset() first is necessary.Trying to simply echo the value would result in an error being thrown when the value does not exist (before the first form is submitted)

---

Otherwise, you can use sessions to achieve this effect:

At the very top of your php page add:

session_start();
$_SESSION['name']=isset($_POST['name']) ? $_POST['name'] :'';

Then in your second form do this:

<input id="name2" class="form-control col-md-7 col-xs-12"  name="other-name" required="required" type="number" value="<?php echo $_SESSION['name']">

Answer 2

If your form action is returning to the same page you can try this:

<form id="form-two">
<input id="name" name="name" value="<?php echo $_POST['name']; ?>">
</form>