[英]How to structure a sql query to get number of mutual friends between users?
I am busy trying to create a query that returns the number of mutual friends between users in a userlist. 我正忙于创建一个查询,该查询返回用户列表中用户之间的共同朋友数。 I have tried a few but they haven't been working as I had hoped, here is one of the queries I have tried
我尝试了一些,但是他们没有按我希望的那样工作,这是我尝试过的查询之一
query("SELECT * FROM userlist WHERE userid = '$userid' AND status ='friend' AND friendid != '$userid' ");
the sql table below renders the relationships between users. 下面的sql表呈现了用户之间的关系。
userid | friendid | type | status |
-----------------------------------
1 |2 | buddy | friend |
-----------------------------------
1 |3 | buddy | friend |
-----------------------------------
2 |3 | buddy | friend |
-----------------------------------
3 |2 | buddy | friend |
-----------------------------------
4 |2 | buddy | friend |
-----------------------------------
3 |1 | buddy | friend |
-----------------------------------
2 |4 | buddy | friend |
------------------------------------
How would I structure a query to find the number of mutual friends between userid 4
and userid 1
. 我将如何构造查询以查找
userid 4
和userid 1
之间的共同朋友数量。
Thanks. 谢谢。
I think this will help, Please note that, here i do not have used condition of "status", you can modify this query as per your requirement. 我认为这会有所帮助,请注意,这里我没有使用“状态”的条件,您可以根据需要修改此查询。
SELECT count(*) FROM userlist as a
INNER JOIN userlist as b
ON(b.friendid=a.friendid and b.userid=4 and b.friendid!=1)
WHERE a.userid=1 and b.friendid!=4
This will return number of mutual friends. 这将返回共同朋友的数量。
As per your data this will give result 1 as for user ID 1 and 4 there is only one mutual friend 2. 根据您的数据,这将为用户ID 1和4给出结果1,只有一个共同的朋友2。
Select friendid
FROM userlist as F
WHERE userid = 1
Select friendid
FROM userlist as S
WHERE userid = 4
Select Distinct *
From F Join S
ON F.friendid = S.friendid
Would give you only the mutual friends of 1 and 4. 只给您1和4的共同朋友。
SELECT Distinct a.friendid as mutual_friend
FROM user_list AS a
JOIN user_list b ON a.friendid = b.friendid
WHERE (a.userid =1 or a.friendid=1)
AND (b.userid =2 or b.friendid=2)
It would give you the Mutual friends id 它会给你共同的朋友id
I made a test Table upon your query and made up a query which will show ids of two friends and no of mutual friends between them. 我根据您的查询创建了一个测试表,并组成了一个查询,该查询将显示两个朋友的ID,而他们之间没有共同的朋友。
SELECT
a.ID as Person1, b.ID as Person2, COUNT(a.FriendID) as NoOfMutualFriends
FROM
Friends a INNER JOIN Friends b
ON a.FriendID = b.FriendID
WHERE a.ID <> b.ID //other filters can be used here
GROUP BY a.ID, b.ID
ORDER BY a.ID
Ask if any Doubts ;) 询问是否有任何疑问;)
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