MySQL-列表结果首先按相同值排序？

Question

I want to get the rows firstly displayed which have the same row data with the country (There is a row that named country). For example if there are 5 results and 2 of them have the country of "England", they should came first. I have tried

$mycountry = "england";
mysql_query("SELECT * FROM members where basresvar='yes' ORDER BY country DESC limit 10")

But it doesnt sort the results as I want. What is the correct way to do that ?

Answer 1

You could write your query this way:

select *
from
  members
where
  basresvar='yes'
order by
  case when country='england' then 1 else 2 end
limit 10

the case...when statement will return 1 when the country='england' and 2 otherwise, then since we are ordering by this statement this will put rows that have country='england' at the top, and others at the bottom.

Answer 2

Use

ORDER BY country = "England" DESC, country

When a comparison is true, the value is 1 ; when it's false the value is 0 . So when you order by this comparison in descending order, the rows where the country is equal to England will be put first.

Adding a second ordering criteria makes all the remaining countries sort alphabetically after England.