从字符串中去除破折号？

Question

For web scraping, I need to match the last part of a URL and replace "-" dashes with " " spaces.

Code looks like this...

<div class="tags">
    <span class="tag" style="background-color: #5A214A;">
        <a href="/Services/Research/Telecoms-software/Service-Assurance/">SA</a>
    </span>
</div>

I want to be left with "Service Assurance" (this part may contain multiple "-" dashes and require multiple replacements).

Currently being used:

Xpath:

//span[@class="tag"]/a/@href

Regex:

/.*/(.*)/

This produces "Service-Assurance", but does not strip out the "-".

I am told elsewhere that this replacement is not possible since I am already using Regex to find the string between the final "/" slashes.

Can I do both? Can I replace the "-" dashes at the end, too?

Regex is plain, inside an app called import.io, no particular language flavour.

Thank-you very much.

Answer 1

Try this xpath without the regex:

//*[@class='tag-wrapper']/input[1]/@value

althernatively you can also try these methods:

I scrape urls in google-sheets all the time with xpaths and regexes - so if you want to try:

=importXML("url goes here","//span[@class="tag"]/a/@href")

now then if you do at least get the url string back, then you know its working ad we can then modify it to this to get what you want:

=SUBSTITUTE(REGEXEXTRACT(importXML("url goes here","//span[@class="tag"]/a/@href"),".*\/(.*)\/$"),"-"," ")

Let me know if you have issues - there are a couple of weird quirks with google - but if you share the url your pulling that xpath in with I can at least test it myself - i use this method now more than any others, I used to use import.io and outwit hub etc a ton