期望的“ spawn”命令是否安全地传递参数？

Question

I have the following expect script which executes 'myexe' and passes some password as argument:

#!/usr/bin/expect
gets stdin pwd

log_user 0

eval spawn "/myexe ${pwd}"

log_user 1
expect eof
catch wait result
exit [lindex $result 3]

My executable 'myexe' is compiled Linux executable (not shell script) and the goal is to pass a password securely to it. Unfortunately the executable doesn't read the stdin for the password, but instead expects it as a start parameter.

When I execute the following expect script I cannot see my 'myexe' executable with 'ps'. Does somebody know if the 'spawn' performed by the expect is secure enough? Would the password be visible somewhere else (/proc for instance)?

Answer 1

Don't use eval here. It could be disastrous, depending on the contents of the password. This should suffice:

spawn /myexe $pwd

Anyone doing a ps -ef while myexe is running will be able to see the password.