无法在jQuery中从左到右获取div动画

Question

I have a list which serves as a menu. Every time user clicks on one of the elements in the list, I want a more detailed div to slide in from left to right.

So if the user was to click menu item A first, A slides from left to right. If the user then clicks B , A slides out from right to left (disappears off screen) and B slides in.

I searched for this problem and found this post . I incorporated the code from the jsfiddle , but it didn't work. No errors are being shown in the js log in Chrome debugging tool. Nothing happens when I click any item from the menu. What am I doing wrong?

 <div class="project">
        <ul id="project_menu" class="project_menu">
            <li id="menu-php-mysql" data-projectID="php-project">PHP/MySQL</li>
            <li id="menu-nodejs" data-projectID="node-project">NodeJS</li> 
            <!-- more code -->
        </ul>
        <div class="project-detail">
            <div id="php-project">
                <i class="ion-ios-close-empty close-icon js-close-icon"></i>
                <div classs="project-text">
                    <!-- data about project -->
                </div>
            </div>
            <div id="node-project">
                <i class="ion-ios-close-empty close-icon js-close-icon"></i>
                <div classs="project-text">
                    <!-- data about project -->
                </div>
            </div>
            <!-- and so on.. -->

#php-project {
    background-color: #9b59b6;
    margin: 30px;
    display: none;
}

$(document).ready(function() {

    itemsToRender = [];

    $('ul#project_menu li').click(function(e) {

        menuItemId = (e.currentTarget.id);

        $('.common').hide();

        $(getProjectId(menuItemId)).css('display', 'inline');

        var value = $(getProjectId(menuItemId)).css('right') === '100px' ? '-100px' : '100px';
        $(getProjectId(menuItemId)).animate({
            right: value                
        }, 800);

    });
});

function getProjectId(menuItemId) {

    if (menuItemId.indexOf('php') > 0) {

        return '#php-project';

    } else if (menuItemId.indexOf('node') > 0) {

        return '#node-project';

    } else if (menuItemId.indexOf('angular') > 0) {

        return '#angular-project';

    } else if (menuItemId.indexOf('mean') > 0) {

        return '#mean-project';

    }          
}

Update1 : @user5325596 pointed out that my display property for the detail div was set to none, so I fixed that by adding the following:

$(getProjectId(menuItemId)).css('display', 'inline-block');

right after $('.common').hide() .

Now, I can see the detail div when I click on the menu item, but it does not animate.

Update2 : I have uploaded a jsFiddle , it includes the jquery animation that I am successfully using (fadeIn, which is commented out), as well as the code suggested by elchininet.

Answer 1

Try with CSS transitions, will save a lot of code. Maybe this is not exactly that you want but I'm sure it'll helps you with your task.

HTML Code

<ul>
  <li>One</li>
  <li>Two</li>
  <li>Three</li>
  <li>Four</li>
  <li>Five</li>
</ul>

CSS Code

li{
  -webkit-transition: all 1s;
  -moz-transition: all 1s;
  transition: all 1s;
}

li.open{
  -webkit-transform: translateX(100px);
  -moz-transform: translateX(100px);
  transform: translateX(100px);
}

jQuery Code

$("li").on("click", function(){

    $("li.open").removeClass("open");

    $(this).addClass("open");

});

jsfiddle

Here you have a jsfiddle with your code modified and the div animations in css .

jsfiddle with part of your code.

Answer 2

Not sure if this is what you need or not

JS Fiddle - updated 2

 // initializing var prevID = '', divs = $('.sliding-divs'); $("li").on("click", function() { var theID, theDiv, theDivW, theCenter; // get the id letter from the li, then pick the corresponding sliding // div depending on its value. theID = $(this).attr('id'); theID = theID.replace('li-', ''); theDiv = $('#div-' + theID); // get the divs width to slide it into the center of the view theDivW = theDiv.width(); theCenter = $(window).width()/2 - theDivW/2; // if the user didn't click the link which its slide already // in the view, this to avoid sliding out and in same div. if(theID != prevID){ if (prevID == '') { // if we don't have a previously slided in div, we just slide // the just click link's div into the view theDiv.animate({'left': theCenter}, 1000); } else { // animated the previous div to the right out of the view, then // move all divs to their original position out from the left // this is because if we don't do this, an already slided div // will later be slided in from right instead in from left // because we have already changed its position. // slide the just clicked link's div into the view from left $('#div-' + prevID).animate({'left': '110%'}, 800); divs.css({'left':-(theDivW + 100)}); theDiv.animate({'left': theCenter}, 1000); } } // change the value of the id representing previously slided in div prevID = theID; }); 

 body { overflow-x: hidden; } ul { list-style: none; padding: 0; } li { width: 100px; height: 25px; margin: 2px 0; color: white; padding: 3px; text-align: center; background-color: green; cursor:pointer; } .sliding-divs { position: absolute; width: 500px; line-height: 250px; background-color: orange; font-size: 30px; border: 2px gold solid; text-align: center; display: inline-block; top: 150px; left: -510px; } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script> <ul> <li id="li-A">item 1</li> <li id="li-B">item 2</li> <li id="li-C">item 3</li> <li id="li-D">item 4</li> </ul> <div class="sliding-divs" id="div-A"> DIV A </div> <div class="sliding-divs" id="div-B"> DIV B </div> <div class="sliding-divs" id="div-C"> DIV C </div> <div class="sliding-divs" id="div-D"> DIV D </div> 

Answer 3

There are some minor mistakes i found on fiddle like , comma between class name. : class="project-container,common"

You are hiding all div with class .common , but not show it after. so its style property get display:none even if you add class open to that div .

Here is my Updated and running code:

 $(document).ready(function() { itemsToRender = []; $('ul#project_menu li').click(function(e) { $('.common').hide(); menuItemId = (e.currentTarget.id); var projectId = getProjectId(menuItemId); console.log(projectId); $('.project-container.open').removeClass('open'); $(projectId).addClass('open'); $(projectId).show(); /* $(projectId).fadeIn('slow'); <--- THIS WORKS! But I want the slide effect instead */ }); function getProjectId(menuItemId) { if (menuItemId.indexOf('php') > 0) { return '#php-project'; } else if (menuItemId.indexOf('node') > 0) { return '#node-project'; } else if (menuItemId.indexOf('angular') > 0) { return '#angular-project'; } else if (menuItemId.indexOf('mean') > 0) { return '#mean-project'; } else if (menuItemId.indexOf('html5-css3-js') > 0) { return '#html-css-js-project'; } } }); 

 .project-detail { float: right; max-width: 50%; margin-right: 75px; color: #fff; } #php-project { background-color:#9b59b6; margin: 30px; display:none; } #node-project { background-color:#27ae60; margin: 30px; display:none; } .project-container{ transition: all 1s; -webkit-transition: all 1s; -moz-transition: all 1s; } .project-container.open{ transform: translateX(-200px); -webkit-transform: translateX(-200px); -moz-transform: translateX(-200px); display: inline-block; } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="project"> <ul id="project_menu" class="project_menu"> <li id="menu-php-mysql" data-projectID="php-project">PHP/MySQL</li> <li id="menu-nodejs" data-projectID="node-project">NodeJS</li> </ul> <div class="project-detail"> <div id="php-project" class="project-container common"> <i class="ion-ios-close-empty close-icon js-close-icon"></i> <div classs="project-text"> <h2 class="project-label">Project title: <span class="project-name"> php project</span></h2> </div> </div> <!-- end of php-project --> <div id="node-project" class="project-container common"> <i class="ion-ios-close-empty close-icon js-close-icon"></i> <div classs="project-text"> <h2 class="project-label">Project title: <span class="project-name"> node project</span></h2> </div> </div> <!-- end of node-project --> </div> <!-- end of project-detail --> </div> <!-- end of project --> 

Answer 4

I think you want this to work like in this fiddle

HTML Code

  <div class="project">
  <ul id="project_menu" class="project_menu">
    <li id="menu-php-mysql" data-projectID="php-project">PHP/MySQL</li>
    <li id="menu-nodejs" data-projectID="node-project">NodeJS</li>
    <!-- more code -->
  </ul>
  <div class="project-detail">
    <div id="php-project">
      <i class="ion-ios-close-empty close-icon js-close-icon"></i>
      <div classs="project-text">
        PHP project text
        <!-- data about project -->
      </div>
    </div>
    <div id="node-project">
      <i class="ion-ios-close-empty close-icon js-close-icon"></i>
      <div classs="project-text">
        Node Project Text
        <!-- data about project -->
      </div>
      <!-- and so on.. -->
    </div>
  </div>
</div>

CSS Code

.project_menu > li{
  cursor: pointer;
}
.project-detail{
  width: 300px;
  height: 100px;
  background-color: #dedede;
  overflow: hidden;
  position: relative;
}

JQuery

$(document).ready(function() {

  $('.project-detail > div:first-child').css("right","0px");
  itemsToRender = [];
  $('#project_menu li').click(function(e) {
        menuItemId = (e.currentTarget.id);

    $('.common').hide();

    $(getProjectId(menuItemId)).css('display', 'inline');
    var value = '0px';
    $(getProjectId(menuItemId)).animate({
      right: '0px'

    }, 800);
    var req = '.project-detail > div';
    $('.project-detail > div').not($(getProjectId(menuItemId))).animate({
        right: '300px'
    }, 800);

  });
});

function getProjectId(menuItemId) {

  if (menuItemId.indexOf('php') > 0) {
    return '#php-project';

  } else if (menuItemId.indexOf('node') > 0) {
    return '#node-project';

  } else if (menuItemId.indexOf('angular') > 0) {
    return '#angular-project';

  } else if (menuItemId.indexOf('mean') > 0) {
    return '#mean-project';

  }
}