循环仅附加在最后一个按钮上

Question

I've made a gui with a variable amount of buttons and entries, dependent on earlier user inputs. I want to store the new entries in a list. My loop however will only append the last entry created in the loop. How can I get each button to append it's respective user entry?

def getFuseType():
          (Fuse.fuseType).append(e.get()
          print(Fuse.fuseType)
for i in range(1,int(Site.NoFuses)+1):
        l = Label(FuseWindow, text = "Fuse Type")
        e = Entry(FuseWindow)
        l.grid(row = 1, column = i+3)
        e.grid(row = 2, column = i+3)          
        b = Button(FuseWindow, text = "ok", command = getFuseType)        
        b.grid(row = 3, column = i+3)

Fuse GUI see the image I've uploaded, The top right 'OK' button appends the entry. I want the top Left button to also append it's respective entry.

Answer 1

The problem is that the function isn't creating a closure around the e variable so they only affect the most recent (last) object assigned to e . If you really want to do this you'll need to use a defaulted arg..

for i in range(1,int(Site.NoFuses)+1):
        l = Label(FuseWindow, text = "Fuse Type")
        e = Entry(FuseWindow)
        l.grid(row = 1, column = i+3)
        e.grid(row = 2, column = i+3)
        def getFuseType(e=e):
            (Fuse.fuseType).append(e.get())
            print(Fuse.fuseType)

        b = Button(FuseWindow, text = "ok", command = getFuseType)        
        b.grid(row = 3, column = i+3)

Answer 2

Get getFuseType out of the for , it is defined every loop iteration and hence you only get the last create entry e

def getFuseType(ent):
    Fuse.fuseType.append(ent)
    print(Fuse.fuseType)

for i in range(1,int(Site.NoFuses)+1):
        l = Label(FuseWindow, text = "Fuse Type")
        e = Entry(FuseWindow)
        ent = e.get()
        l.grid(row = 1, column = i+3)
        e.grid(row = 2, column = i+3)    
        b = Button(FuseWindow, text = "ok", command = lambda ent = ent:getFuseType(ent))        
        b.grid(row = 3, column = i+3)