[英]PHP/SQL Sum total customer count
My database has duplicates for different reasons, and I am trying to get a total of unique customers per a users ID. 由于不同的原因,我的数据库存在重复项,因此,我试图通过一个用户ID获得总计唯一身份的客户。
This is the current query that I have constructed. 这是我构建的当前查询。
$ApprovedCustomerCount ="SELECT `".Customer_Full_Name."`, `".Customer_Address."`, COUNT(DISTINCT(`".Customer_Full_Name."`)) AS CustomersCount
FROM `".OrdersTable."`
WHERE `".Users_Sales_ID."`=$EMPID
AND `".Current_Order_Stage."`='".Current_Order_Stage_Approved."'
GROUP BY `".Customer_Full_Name."`, `".Customer_Address."`
HAVING COUNT(".Customer_Full_Name.") > 1";
$ApprovedCustomerResult=mysql_query($ApprovedCustomerCount);
while($OrdersRow=mysql_fetch_array($ApprovedCustomerResult))
$CustomerApprovedCount = $OrdersRow['CustomersCount'];
if (empty($CustomerApprovedCount)) { $CustomerApprovedCount = '0'; }
echo $CustomerApprovedCount;
Mistakenly, it only gives me a value of 1
when I echo in PHP. 错误地,当我在PHP中回显时,它只给我一个值1
。
However, when I query the DB Table with the exact query I get an output ( for each customer name, address that are unique counts = 1) that will display the list of customers, and give me db row count of 67
. 但是,当我使用确切的查询查询数据库表时,我得到一个输出(对于每个客户名,唯一计数的地址= 1),该输出将显示客户列表,并给我db行计数67
。 That is the number I need. 那是我需要的电话号码。
Query in PhpMyAdmin I run 在我运行的PhpMyAdmin中查询
SELECT `CustomerName`, `CustomerAddress`, COUNT(DISTINCT(`CustomerName`)) AS Customers
FROM `wrightway_orders`
WHERE `Employee_ID` = '3020'
AND `Order Stage`='Approved'
GROUP BY `CustomerName`, `CustomerAddress`
HAVING COUNT(*) > 1
Outputs 输出
+------------------+----------------------+----------------+
| Customer Name | Address | CustomersCount |
+------------------+----------------------+----------------+
| ADRIANE JOHNSON | 10015 161ST PL NE | 1 |
+------------------+----------------------+----------------+
| BILL SMITH | 9923 161ST AVE NE | 1 |
+------------------+----------------------+----------------+
| BRIAN WALTERS | 11129 106TH AVE NE | 1 |
+------------------+----------------------+----------------+
etc 等等
I need to sum the total amount of Count defined as 'CustomerCount'
values to then echo that value as echo $CustomerApprovedCount;
我需要对Count defined as 'CustomerCount'
值的Count defined as 'CustomerCount'
总数求和 ,然后将该值作为echo $CustomerApprovedCount;
Where am I going wrong? 我要去哪里错了?
I appreciate your help :) 我感谢您的帮助 :)
I need to count all customers that are unique, then give a sum total of all customers where Employee_ID=ID#. 我需要计算所有唯一的客户,然后给出Employee_ID = ID#的所有客户的总和。
Just use mysql_num_rows
with result: 只需将mysql_num_rows
与结果配合使用:
$ApprovedCustomerResult = mysql_query($ApprovedCustomerCount);
$CustomerApprovedCount = mysql_num_rows($ApprovedCustomerResult);
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