[英]How can I get all points within a given range based on its latitude and longitude?
scenario: I have a db with three tables, users, locations, stock; 场景:我有一个包含三个表,用户,位置,库存的数据库;
within users I have: id, name, email
在我拥有的用户中:
id, name, email
within locations I have: id, place, lati, logi
在我所拥有的位置:
id, place, lati, logi
within stock I have: id, user_id, product, total_count, location_id
我有股票:
id, user_id, product, total_count, location_id
I am fairly new and I managed to join all the tables: 我很新,我设法加入所有表格:
$qry = "
SELECT COUNT(id)
FROM stock
LEFT
JOIN users
ON stock.user_id= users.id
LEFT
JOIN locations
ON stock.location_id= locations.id ";
But what I am hoping to be able to do is sort it by distance using the lati and logi. 但我希望能够做的是使用lati和logi按距离对其进行排序。 So for example, I want everything within 25 miles, sorted closest to furthest.
因此,例如,我希望25英里内的所有内容,最接近最远的排序。
How can i pull this off giving the scenario? 我怎样才能解决这个问题呢?
I did some googling but everything i'm finding show me how I can get the distance between two points, but what I want to be able to use one set of points, and get everything within X miles of it? 我做了一些谷歌搜索,但我发现的一切都告诉我如何获得两点之间的距离,但我希望能够使用一组点,并获得X英里内的所有内容?
Not sure if that all makes sense ? 不确定这一切是否有意义?
I have come up with below simplified formula for calculating this in my application : 我在我的应用程序中提出了以下简化公式来计算:
pow(CentralLati - LatitudeofCircle, 2) + pow(CentralLongi - LongitudeofCircle, 2) <= 4
where, 哪里,
CentralLati , CentralLongi => co-ordinates of a point A CentralLati,CentralLongi => A点的坐标
LatitudeofCircle, LongitudeofCircle => co-ordinates of the points 25kms around the point A. LatitudeofCircle,LongitudeofCircle =>点A周围25kms点的坐标。
You may adjust the above formula to match your database naming conventions. 您可以调整上面的公式以匹配您的数据库命名约定。
Hope I understood your requirement correctly. 希望我能正确理解你的要求。
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