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如何根据纬度和经度获得给定范围内的所有点?

[英]How can I get all points within a given range based on its latitude and longitude?

scenario: I have a db with three tables, users, locations, stock; 场景:我有一个包含三个表,用户,位置,库存的数据库;

within users I have: id, name, email 在我拥有的用户中: id, name, email

within locations I have: id, place, lati, logi 在我所拥有的位置: id, place, lati, logi

within stock I have: id, user_id, product, total_count, location_id 我有股票: id, user_id, product, total_count, location_id

I am fairly new and I managed to join all the tables: 我很新,我设法加入所有表格:

$qry = "
SELECT COUNT(id)
  FROM stock
  LEFT
  JOIN users 
   ON stock.user_id= users.id
  LEFT
  JOIN locations
   ON stock.location_id= locations.id ";

But what I am hoping to be able to do is sort it by distance using the lati and logi. 但我希望能够做的是使用lati和logi按距离对其进行排序。 So for example, I want everything within 25 miles, sorted closest to furthest. 因此,例如,我希望25英里内的所有内容,最接近最远的排序。

How can i pull this off giving the scenario? 我怎样才能解决这个问题呢?

I did some googling but everything i'm finding show me how I can get the distance between two points, but what I want to be able to use one set of points, and get everything within X miles of it? 我做了一些谷歌搜索,但我发现的一切都告诉我如何获得两点之间的距离,但我希望能够使用一组点,并获得X英里内的所有内容?

Not sure if that all makes sense ? 不确定这一切是否有意义?

I have come up with below simplified formula for calculating this in my application : 我在我的应用程序中提出了以下简化公式来计算:

pow(CentralLati - LatitudeofCircle, 2) + pow(CentralLongi - LongitudeofCircle, 2) <= 4

where, 哪里,

CentralLati , CentralLongi => co-ordinates of a point A CentralLati,CentralLongi => A点的坐标

LatitudeofCircle, LongitudeofCircle => co-ordinates of the points 25kms around the point A. LatitudeofCircle,LongitudeofCircle =>点A周围25kms点的坐标。

You may adjust the above formula to match your database naming conventions. 您可以调整上面的公式以匹配您的数据库命名约定。

Hope I understood your requirement correctly. 希望我能正确理解你的要求。

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