[英]jQuery doesn't seem to be working on browsers
I'm trying to hide/display fields according to which selection is made in a drop down menu. 我试图根据在下拉菜单中所做的选择隐藏/显示字段。
The code for the jQuery doesn't seem to be taking. jQuery的代码似乎没有占用。 Any suggestions?
有什么建议么? New to jQuery.
jQuery新手。 I'm saving my files as .php
我将文件另存为.php
jQuery: jQuery的:
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<script type="text/javascript">
$(document).ready(function() {
$.viewMap = {
'0' : $([]),
'view1' : $('#view1'),
'view2' : $('#view2a, #view2b'),
'view3' : $('#view3')
};
$('#viewSelector').change(function() {
// hide all
$.each($.viewMap, function() { this.hide(); });
// show current
$.viewMap[$(this).val()].show();
});
});
</script>
</head>
html: HTML:
<select id="viewSelector">
<option value="0">-- Select a View --</option>
<option value="view1">view1</option>
<option value="view2">view2</option>
<option value="view3">view3</option>
</select>
<select id="viewSelector">
<option value="0">-- Select a View --</option>
<option value="view1">view1</option>
<option value="view2">view2</option>
<option value="view3">view3</option>
</select>
<div id="view1">
<!-- content -->
</div>
<div id="view2a">
<!-- content -->
</div>
<div id="view2b">
<!-- content -->
</div>
<div id="view3">
<!-- content -->
</div>
You have a duplicate <select>
. 您有一个重复的
<select>
。 If you remove it, the view selector works: 如果删除它,则视图选择器将起作用:
If there are any jQuery issues occurring behind the scenes due to code outside of what you posted, press F12 in Chrome to open the DevTools , and click the Console tab to see any JavaScript errors after refreshing the page. 如果由于您发布的代码之外的代码而在后台发生任何jQuery问题,请在Chrome中按F12打开DevTools ,然后在刷新页面后单击“ 控制台”选项卡以查看任何JavaScript错误。
Ids should be unique. ID应该是唯一的。 In your code, there are 2 selects with same id
viewSelector
. 在您的代码中,有2个具有相同id
viewSelector
选择。 You may remove one set. 您可以删除一组。
Give each div a common class like; 给每个div一个普通的类,例如;
<div class="views" id="view3">
Then try to hide all divs using this class. 然后尝试使用此类隐藏所有div。 Then show the required div on drop down select.
然后在下拉菜单中显示所需的div。 The entire code may look like;
整个代码可能看起来像;
$.viewMap = {
'0': $([]),
'view1': $('#view1'),
'view2': $('#view2a, #view2b'),
'view3': $('#view3')
};
$('#viewSelector').change(function() {
// hide all
$(".views").hide();
// show current
$.viewMap[$(this).val()].show();
});
Please try below code: 请尝试以下代码:
jQuery: jQuery的:
$(document).ready(function() {
$('#viewSelector').change(function() {
$('.view').hide();
// show current
if($(this).val() !== 0){
if($(this).val() == "view2"){
$("#view2a, #view2b").show();
}else{
$("#"+ $(this).val()).show();
}
}
});
});
HTML: HTML:
<select id="viewSelector">
<option value="0">-- Select a View --</option>
<option value="view1">view1</option>
<option value="view2">view2</option>
<option value="view3">view3</option>
</select>
<div id="view1" class="view">
<!-- content -->
</div>
<div id="view2a" class="view">
<!-- content -->
</div>
<div id="view2b" class="view">
<!-- content -->
</div>
<div id="view3" class="view">
<!-- content -->
</div>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.