将文本文件的当前行打印到文本文件的前一行

Question

I have a text file that I'm trying to process. The data is in the form of:

1002001             1             1             1             1                1
+                   1        1.0e-4       1.24012        1.0e-4          0.44
+              1.0e-4          0.44           1.0           0.0           1.0
+                 0.0           1.0           0.0           0.0           0.0
+                 0.0           0.0           0.0           0.0           0.0

I would like to take all the lines that start with + and move them to the line that starts with '1002001', like this (kind of like sed -r ':a;N;s/\\n^\\+//g;ba ):

1002001 1 1 1 1 1 1 1.0e-4 1.24012 1.0e-4 0.44 1.0e-4 0.44 1.0 0.0 1.0 0.0 1.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0

Answer 1

这样的事情怎么样：

(Get-Content yourfile.txt -Raw) -replace '[\r\n]+\+', ''