在 JavaScript 中使用随机时间的“setinterval”

Question

I have this setinterval with function alert:

setInterval(function(){
    alert('oo');
}, 5000);

But I would like to change my (5000) interval each time interval runs alert() - I'd like have it randomly selected between 5 - 10 seconds. How can I do it?

Answer 1

You should use setTimeout to set interval after which the function should be executed.

 function myFunction() { var min = 5, max = 10; var rand = Math.floor(Math.random() * (max - min + 1) + min); //Generate Random number between 5 - 10 console.log('Wait for ' + rand + ' seconds'); setTimeout(myFunction, rand * 1000); } myFunction()

Answer 2

You can do it like this:

 function myFunction() { alert('oo'); setTimeout(myFunction, Math.random() * 5000) } myFunction()

Answer 3

You can do this with two methods, first setTimeout and second requestAnimationFrame .

Here are the full examples of both.

Random interval with setTimeout

function randomInterval(callback, min, max) {
    let timeout;

    const randomNum = (max, min = 0) => Math.random() * (max - min) + min;

    const stop = () => clearTimeout(timeout)

    const tick = () => {
        let time = randomNum(min, max);
        stop();

        timeout = setTimeout(() => {
            tick();
            callback && typeof callback === "function" && callback(stop);
        }, time)
    }

    tick();
}

Random interval using requestAnimationFrame

function randomInterval(callback, min, max) {
    const randomNum = (max, min = 0) => Math.random() * (max - min) + min;

    let targetTime = randomNum(min, max);
    let lastInvoke = performance.now();

    const stop = () => targetTime = null

    const tick = () => {
        if (!targetTime) return;

        if (performance.now() - lastInvoke > targetTime) {
            lastInvoke = performance.now();
            targetTime = randomNum(min, max);
            callback && typeof callback === "function" && callback(stop);
        }

        requestAnimationFrame(tick)
    }

    tick();
}

and here is an example of how to call it

randomInterval((stop) => {
    // do what you want...

    if (stopCondition) {
        stop();
    }
}, 1000, 3000)

Answer 4

Intervals, once set, are fixed.

Use setTimeout and call the function recursively instead.

function myAlert() {
    setTimeout(myAlert, generate_random_time());
    alert('oo');
}

Answer 5

The only potential issue with most of the current answers here is that the initial function call does not have the random delay, only the subsequent calls.

A modification is to place the function outside the loop then call it inside the setTimeout:

function doSomething() {
    console.log("Hello");
}

(function loop() {
    var rand = Math.round(Math.random() * 10);
    setTimeout(function() {
            doSomething();
            console.log("Delayed " + rand + " secs.");
            loop();  
    }, rand*1000);
}());

Learning ES6 converting to arrow functions and template literals the code looks like:

function doSomething() {
    console.log("Hello");
}

(function loop() {
    let rand = Math.round(Math.random() * 10);
    setTimeout( () => {
            doSomething();
            console.log(`Delayed ${rand} secs`);
            loop();  
    }, rand*1000);
}());

Adapted from a very similar thread:https://stackoverflow.com/questions/6962658/randomize-setinterval-how-to-rewrite-same-random-after-random-interval