正则表达式-匹配parsley.js中的整个单词

Question

How do I match two entire words with or(|) operand in parsley.js' data-parsley-pattern attribute?

As you can see I want to match the words user and moderator .

I have tried: data-parsley-pattern="/(user|moderator)/" which is normal regex and works with other standardised regular expression matching like regex101.com: https://regex101.com/r/kD7sR1/1

Answer 1

See the data-parsley-pattern 2.0 documentation :

Validates that a value matches a specific regular expression (regex). Note that patterns are anchored, ie must match the whole string. Parsley deviates from the standard for patterns looking like /pattern/{flag} ; these are interpreted as litteral regexp and are not anchored.

So, it looks like your regex should work.

If it does not, try

data-parsley-pattern="/[\s\S]*(user|moderator)[\s\S]*/"

The [\\s\\S]* will match zero or more characters (any, including newlines).

Answer 2

Your pattern should work, as long as you are using a full form with /.../ , otherwise the pattern would be anchored. You don't even need the parenthesis but they won't hurt either.

Here's a working demo that simply uses

<input data-parsley-pattern="/user|moderator/" type="text" name="fullname" required>