preg_match() 失败，字符串包含斜线

Question

I have a function like this:

function in_array_r($item , $array){
        return preg_match('/"'.$item.'"/i' , json_encode($array));
}

and then I use it like:

if(in_array_r($row['name'], $items_array)){
   // something..
}

It works unless the $row['name'] contains something like blah / blah / something , in which case it says that it can't find it in the array, even though it exists.

How do I fix this?

Answer 1

This is because the slash in your input: blah / blah / something is seen as delimiter for the regex.

To solve this you can escape your input with preg_quote() , eg

function in_array_r($item , $array){
    return preg_match('/"'.  .'"/i' , json_encode($array));
}

Answer 2

I know this in an old question, but I wanted to share that I resolved this, simply by using a different delimiter, eg

$var = 'string with /// slashes';
preg_match("~.*?$var.*?~i", $string);

This is a perfectly valid syntax in PHP.