Ruby nokogiri解析正则表达式

Question

I am parsing a webpage using the following code:

@doc = Nokogiri::HTML(open(url))
links = @doc.css("span[class='reviewCount']").css('a')
links.each do |link| 
  link["href"]
end

I get a list of href reference as follows

/Restaurant_Review-g187147-d719052-Reviews-Epicure-City_Ile_de_France.html#REVIEWS
/Restaurant_Review-g187147-d6958622-Reviews-Seb_on-City_Ile_de_France.html#REVIEWS
/Restaurant_Review-g187147-d8766885-Reviews-Le_cherine-City_Ile_de_France.html#REVIEWS

I am trying to get the substring between Reviews- and -City

Epicure
Seb_on
Le_cherine

by replacing

  link["href"]

by

  link["href"][[/\"Reviews-"(.*?)"-City"/, 1]

but I do not manage to find the right syntax. Could anyone help me to find correct syntax? Thanks.

Answer 1

/Reviews-((.)+)-City/ is the regexp to extract "WHATIWANT" from "XX-Reviews-WHATIWANT-City-XX"

 "XX-Reviews-WHATIWANT-City"[/Reviews-((.)+)-City/, 1]
 #=> "WHATIWANT"

Full solution:

require 'nokogiri'

html = <<-EOF
<span class="reviewCount">
<a href="XX-Reviews-WHATIWANT-City-XX" target="_blank" onclick="XX;">1,361 reviews</a>
</span>
EOF

doc = Nokogiri::HTML(html)
doc.xpath("//span[@class='reviewCount']/a").each do |node|
  puts node.attribute("href").to_s[/Reviews-((.)+)-City/, 1]
end