SQLALCHEMY：没有唯一约束匹配给定键的引用表

Question

I'm trying to create a relationship between my tables seller and item where each seller can sell any number of items but they can't sell the same item twice. Here's what I have:

sells = db.Table('sells',
     db.Column('seller_email', db.String(), db.ForeignKey('seller.email'), primary_key=True),
     db.Column('item_id', db.Integer, ForeignKey('item.id'), primary_key=True)
)

class Item(db.Model):
     __tablename__ = 'item'

     id = db.Column(db.Integer, primary_key=True)
     coverPhoto = db.Column(db.String())
     price = db.Column(db.Integer)
     condition = db.Column(db.Integer)
     title = db.Column(db.String())

     def __init__(self, title, coverPhoto, price, condition):
         self.coverPhoto = coverPhoto
         self.price = price
         self.condition = condition
         self.title = title

     def __repr__(self):
         return '<id {}>'.format(self.id)

class Seller(db.Model):
     __tablename__ = 'seller'

     email = db.Column(db.String(), primary_key=True)
     password = db.Column(db.String())
     firstName = db.Column(db.String())
     lastName = db.Column(db.String())
     location = db.Column(db.String())

     def __init__(self, email, password, firstName, lastName, location):
         self.email = email
         self.password = password
         self.firstName = firstName
         self.lastName = lastName
         self.location = location

     def __repr__(self):
         return "<Seller {email='%s'}>" % (self.email)

And I get the following error:

sqlalchemy.exc.ProgrammingError: (psycopg2.ProgrammingError) there is no unique constraint matching given keys for referenced table "seller"

[SQL: '\nCREATE TABLE sells (\n\tseller_email VARCHAR NOT NULL, \n\titem_id INTEGER NOT NULL, \n\tPRIMARY KEY (seller_email, item_id), \n\tFOREIGN KEY(item_id) REFERENCES item (id), \n\tFOREIGN KEY(seller_email) REFERENCES seller (email)\n)\n\n']

Bother seller.email and item.id are primary keys so shouldn't they inherently be unique?

Answer 1

You're creating the table sells using db.Table , a SQLAlchemy Core function. Nothing wrong with that. Then you create your other tables by inheriting from db.Model using the SQLAlchemy ORM's declarative syntax. (If you're not familiar with the difference between SQLAlchemy Core and ORM, the tutorial is a good place to start.)

You've got a couple of potential issues here:

1. You're using db.Model and the SQLAlchemy ORM's declarative syntax. When you do this, your model subclasses don't need an __init__ function. In fact, using an __init__ likely will cause problems (possibly even the root cause here) as it will interfere with the monkey-patching that SQLAlchemy does to make the Declarative syntax so convenient...

2. I suspect that the root cause here might actually be that you use SQLAlchemy Core to create a table with a foreign key reference to a SQLAlchemy ORM-managed table. Normally, when you do db.metadata.create_all() , SQLAlchemy will collect all the table/model mappings, look at the dependencies and figure out the correct ordering for emitting the CREATE TABLE / ADD CONSTRAINT commands to the database. This under-the-covers dependency resolving is what allows the app programmer to define a table that includes a foreign key to a table that is defined later. When you have a Core-based Table object that references a ORM db.Model -based object, it might prevent the dependency resolving from working correctly during table creation. I'm not 100% confident this is the issue, but it's worth experimenting with making all your tables either Table objects, or db.Model subclasses. If you're not sure, I'd suggest the latter.