使用PHP SSH进入计算机

Question

I'm trying to

• SSH into my VM
• Go to a specific directory
• Run a Script

---

My command

ssh user@45.12.129 "cd ~/scripts; pwd; ./startVM.sh"

---

PHP

$cmd = 'ssh user@45.12.129 "cd ~/scripts; pwd; ./startVM.sh";
$data = shell_exec($cmd);

I'm not sure when to input my password. I hope someone can fill out what I missed.

Answer 1

The easiest (though not necessarily most secure) way would be to create an passwordless ssh key and add that to your VM:

• run ssh-keygen to create a new public/private keypair if you haven't already (or if you want to create a new key just for this purpose)
• Put the generated public key in ~/.ssh/authorized_keys for the user in the VM. Make sure this file is only readable and writable by the target user. (It should have mode 0500.)
• ssh will now work without a password. (In effect, the private key is the password.)
• If you want to specify a specific key to use, specify with ssh -i path-to-key-file .

Warning: Keep in mind that allowing remote code execution can be very dangerous, especially when the target is the root account. If this were a local VM, you should be relatively safe, but do be cautious when using this technique in general, especially over the internet. You can very easily shoot yourself in the foot like this.

You probably want to create a non-root user in your VM for this purpose. If that user requires root privileges to complete its task, then grant access only to the specific functionality it needs with sudo and an appropriate sudoers file entry.

Answer 2

Can you try something like this?

        if(!($con = ssh2_connect($ip, $port))){
            echo'cannot connect';
        } else {
            //Auth
            if(!ssh2_auth_password($con, "userssh", "password")) {
                echo'authentication failed';
            } else {
                //Execute command
                if(!($stream = ssh2_exec($con, "cd ~/scripts; pwd; ./startVM.sh" )) ){
                    echo 'failed executing';
                } else {
                     echo 'sucess';

                }
            }
         }