自定义MYSQL计数结果的排序顺序？

Question

I am trying to write a report on some data I collected using a google form. Each person was asked how many of an item they had in their closet. I want to present the data as a count of how many out of the total fell into each range. So, I used this mysql query to count the instances of each answer:

SELECT  `Closet` , COUNT( * ) FROM  `TABLE 1` GROUP BY  `Closet`

And here is the resulting data:

Closet  | COUNT( * )
--------+------------
0       | 8
1-5     | 124
101-200 | 7
11-20   | 181
201-300 | 3
21-50   | 171
51-100  | 48
6-10    | 156

The problem is that alphabetically, 101-200 items sorts before 6-10 items. I basically want to sort this in some way that would put the number ranges in a logical order. (1-5, 6-10, 11-20, etc).

How can I accomplish this?

Answer 1

You'll have to use convert & substring_index .

SELECT `Closet` , COUNT( * ) FROM `TABLE 1` GROUP BY `Closet` order by convert(substring_index(Closet,'-',1), unsigned integer) 

This will sort the Closet by taking the first number of the ranges, which should essentially do the job.