简体   繁体   English

在选择查询中按个案排序

[英]Order by and case in select query

users
id | status | qualified
1  | yes    | BE
2  | no     | BCOM
3  | no     | BSC
4  | no     | BE
5  | yes    | BE

I want users with qualified = BE to fetch first then with status yes then other users 我希望具有合格= BE的用户先获取,然后以状态yes取,然后再获取其他用户

I have written query as follows but not getting result as expected 我写了如下查询,但没有得到预期的结果

SELECT * 
FROM users 
ORDER BY 
CASE WHEN qualified =  'BE'
THEN 0
 WHEN status =  'yes'
THEN 0  
ELSE 1 
END

In MySQL comparing results in 0 and 1 . 在MySQL中,比较结果为01 So you can do 所以你可以做

SELECT * 
FROM users 
ORDER BY qualified <> 'BE',
         status <>  'yes'

and generally you could do 通常你可以做

SELECT * 
FROM users 
ORDER BY case when qualified = 'BE' then 1 else 2 end,
         case when status = 'yes' then 1 else 2 end

You can also do something like 您也可以做类似的事情

select case when qualified = 'BE' Then 1 When status = 'Yes' then 2 else 3 End as Ranking, * from users order by Ranking 当合格='BE'时选择大小写,然后1当状态='是'时再选择2,否则3以排名结束,*来自用户,按排名排序

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM