从右到左获取字符串中子字符串的下一个匹配项（Java）

Question

Say I have a string s like this:

s = "... *begin* - some-code-here - *end* ..."
i:                    ^

and an index i pointing to a position between "*begin*" and "*end*" , eg, to the 'e' of "some" .

To get the index of the (next) occurrence of "*end"* , I could use

s.indexOf("*end*", i)

Is there a similar way to get the index of the next "*begin*" to the left?

Answer 1

采用

s.lastIndexOf("*begin*", i);

Answer 2

I want this answer to add as comment to wero's answer but due to low reputation I am unable to do so.

I think it should be like

s = s.substring(0, i);

s.indexOf("*begin");