如何通过 START 命令运行多个命令

Question

I have a case where I need to spawn multiple CMD instances (using the START program), and each instance needs to run some commands in sequence . These commands are generated by a batch script, so they are not known ahead of time.

Basically, what I'm looking to do is something like the following, but I don't know the proper syntax (or if it's even possible):

START (program_a && program_b && program_c)

Obviously, those parentheses are incorrect syntax. So when I try to run some syntactically correct variant(s):

START program_a && program_b && program_c

I just end up with one CMD instance being spawned, running program_a , and the "owning" batch script continues to execute program_b and program_c on its own (ie not in the CMD instance spawned by START ).

Answer 1

I think, you need something like:

start "MyWindow" cmd /c "ping localhost & ipconfig & pause"

Answer 2

It helps to escape every & with ^& :

START program_a ^&^& program_b ^&^& program_c

Answer 3

Trying in a batch file, but the two commands (:vexe! and move) are executed at the same time :

start "" /d "!mpwd!" /low /affinity !hex! /b cmd /v:on /c " 1^>"%lcpu%.!cnxt!" 2^>^&1 !vexe! !vcmd! && move /y "%%a" "!mrel!" "

Tried with escaping the && or not, putting the move into parenthesis as well. No luck there...

Any advice?