在jQuery中执行SQL查询，以便从HTML表和数据库中删除数据

Question

i have a html table which displays columns -client name,staff name, matter and delete. my delete column contains only buttons for each row.And my data base contains columns id,date ,client name, staff name and matter.My database does not contain delete column,it is just displayed in my html table.now i want to delete particular row on click of corresponding delete button in that row.just check out my jquery code and sql code and let me know why is it not working? jquery code-

 $(document).ready(function()
{
    $('input[type=button]').click(function()
    {
        if (confirm("Are you sure you want to delete this row?"))
        {
            var id = $(this).parent().parent().attr('id');
            var data = 'id=' + id ;
            var parent = $(this).parent().parent();

            $.ajax(
            {
                   type: "POST",
                   url: "delete.php",
                   data: data,
                   cache: false,

                   success: function()
                   {
                    parent.fadeOut('slow', function() {$(this).remove();});
                   }
             });
        }
    });


});

my sql code -

<?php
include 'db.php' // DB Connection
if($_POST['id'])
{
    $ID = mysql_escape_string($_POST['id']);

    $sql = "DELETE FROM `newdata` WHERE id = '$ID'";
    mysql_query($sql);
}

?>

and my html goes like this-

   <table class="footable" data-filter="#filter" id="tableresult">
                               <thead>

                                <th>Client name</th>
                                 <th>Staff name</th>
                                 <th>Matter</th>
                                 <th> Delete</th>
                              </thead>
<tr id="<?php echo $id; ?>" class="edit_tr">

<td class="edit_td" >
<span id="client_<?php echo $id; ?>" class="text"><?php echo $clientname; ?></span>
<input type="text" value="<?php echo $clientname; ?>" class="editbox" id="client_input_<?php echo $id; ?>" /&gt;
</td>

<td class="edit_td">
<span id="staff_<?php echo $id; ?>" class="text"><?php echo $staff; ?></span> 
<input type="text" value="<?php echo $staff; ?>" class="editbox" id="staff_input_<?php echo $id; ?>"/>
</td>

<td class="edit_td">
<span id="matter_<?php echo $id; ?>" class="text"><?php echo $matter; ?></span> 
<input type="text" value="<?php echo $matter; ?>" class="editbox" id="matter_input_<?php echo $id; ?>"/>
</td>
<div id ="delete_btn">
<td class="delete_td"><input type="button" id="del" class="btn btn-danger" value="&times;"></input></td>
</div>
</tr>

Answer 1

HTML

I've removed the <div> you had wrapped around your final <td> because that's bad markup. Rely, instead on the button itself, which has also been changed from an <input> to <button> . I've also added a data-id attribute to the button, so you can more easily access the row id. Finally, I've removed the id="del" attribute, as I would imagine this is in a loop and all your buttons will then have the same id which does you no good. Class was added btn-delete to target click events.

<tr id="<?php echo $id; ?>" class="edit_tr">

    <td class="edit_td" >
        <span id="client_<?php echo $id; ?>" class="text">
        <?php echo $clientname; ?>
        </span>
        <input type="text" value="<?php echo $clientname; ?>" class="editbox" id="client_input_<?php echo $id; ?>" /&gt;
    </td>

    <td class="edit_td">
        <span id="staff_<?php echo $id; ?>" class="text">
        <?php echo $staff; ?>
        </span> 
        <input type="text" value="<?php echo $staff; ?>" class="editbox" id="staff_input_<?php echo $id; ?>"/>
    </td>

    <td class="edit_td">
        <span id="matter_<?php echo $id; ?>" class="text">
        <?php echo $matter; ?>
        </span> 
        <input type="text" value="<?php echo $matter; ?>" class="editbox" id="matter_input_<?php echo $id; ?>"/>
    </td>

    <td class="delete_td">
        <button data-id="<?php echo $id; ?>" class="btn btn-danger btn-delete" value="&times;" />
    </td>
</tr>

JavaScript / jQuery

The jQuery is fairly simple. We create an eventListener for the class .btn-delete which is on your delete button. Then it grabs the data-id attribute of the button that was clicked and calls your PHP with an $.ajax() call. On success of that call, we run a callback function called removeRow() which will remove the front-end <tr> element. Inside that callback function, there's a simple var time that controls the transition time to remove the row, which is a two-step procedure. First, it slides up the row and then it will remove the element from the DOM .

<script type="text/javascript">
    $( document ).ready( function() {

        // A Delete Button Was Clicked
        $( document ).on( 'click', '.btn-delete', function() {

            // Get the ID we're going to delete
            var delID = $( this ).attr('data-id');

            // Run Our Ajax
            $.ajax({
                url: "delete.php",
                type: "POST",
                data: "?id=" + delID,
                success: function() {
                    removeRow(delID);
                },
                error: function() {
                    alert('Something went wrong');
                }
            });

        } );

        // Callback function to remove row
        function removeRow( id ) {
            var time = 500;
            $( 'tr#' + id ).slideUp(time);
            setTimeout( function() { $( 'tr#' + id ).remove(); }, time );
        }

    } );
</script>

PHP

I'm going to assume your php is deleting the row properly already, so it can probably just remain the same.

Answer 2

guys finally got it and thanks for your help and support-

my jquery code-

$(document).ready(function()
{
    $('input[type=button]').click(function()
    {
        if (confirm("Are you sure you want to delete this row?"))
        {
            var ID = $(this).parent().parent().attr('id');
            var data = 'id=' + ID ;
            var parent = $(this).parent().parent();

            $.ajax(
            {
                   type: "POST",
                   url: "delete.php",
                   data: data,
                   cache: false,

                   success: function()
                   {
                    parent.fadeOut('slow', function() {$(this).remove();});
                   }
             });
        }
    });


});

my sql code-

<?php
include("db.php");
if($_POST['id'])
{
    $id = mysql_escape_string($_POST['id']);

    $sql = "DELETE FROM newdata WHERE id = '$id'";
    mysql_query($sql);
}

?>