CakePHP-单独对结果数组进行排序

Question

Using CakePHP 2.7, I have an array of find results:

array(
    (int) 0 => array(
        'Foo' => array(
            'id' => '786',
            'bar_id' => '12',
            // more data
        ),
        'Bar' => array(
            'id' => '12',
            // more data
        )
    ),
    (int) 1 => array(
        'Foo' => array(
            'id' => '785',
            'bar_id' => '13',
            // more data
        ),
        'Bar' => array(
            'id' => '13',
            // more data
        )
    ),
    // many more results

Now I want do have it sorted by 'bar_id' in a defined individual way, not numeric . The sort order is described in another array:

array(9, 3, 18, 36, …)

Is there a better way to do it but to loop over the sort array, pick the current id then loop over the results array (a loop within a loop), look there for the corresponding 'bar_id' and if found write the result into a new results array?

$results = array(…); // the results
$order = array(9, 3, 18, 36, …);
$sortedResults = array();
foreach ($order as $barId) {
    foreach ($results as $result) {
        if ($barId == $result['Foo']['bar_id']) {
            $sortedResults[] = $result;
            break;
        }
    }
}

I know that Cake has the Hash utility (formerly 'Set') to work with arrays, but I couldn't find a way to do it with Has.

Answer 1

I would do this way:

$indexed_results = Hash::combine($results , '{n}.Foo.bar_id', '{n}');

foreach($order as $index)
{
    $sortedResults[] = $indexed_results[$index];
}

the first row replaces the index in $results with the corrispondant value of bar_id so you can do a single loop

edit: probably you'll have to check that the $index actually exists in your array unless you're sure that every value in $order has a correspondent bar_id otherwise you'll get a "Undefined index" notice