如何在SpringMVC和Hibernate中从JSON响应中获取日期格式响应而不是毫秒

Question

I am doing a sample of rest services using springmvc and hibernate,in which i am getting date response in millisecond format for date datatype,i have used below code by google search,but there is no effect of those code it results same milliseconds format.below is my code used

controller.java

/* Getting List of objects in Json format in Spring Restful Services */  
 @RequestMapping(value = "/list", method = RequestMethod.GET)  
 public @ResponseBody  List getDatalist() { 
  List DataList = null;  
  try {  
      DataList = dataServices.getDataEntityList();  
  } catch (Exception e) {  
   e.printStackTrace();  
  }  
  return DataList;  
 }   

DataValueTable.java

  @JsonAutoDetect
@Entity  
@Table(name = "DataValueTable")  
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})  
public class DataValueTable  implements Serializable {  

 private static final long serialVersionUID = 1L;  

 @Id  
 @GeneratedValue  
 @Column(name = "ID")  
 private long id;  

 @JsonSerialize(using=JsonDateSerializer.class)
 @Column(name = "Datatype") 
 private Date dataType;  

 @Column(name = "Datacategory")  
 private String dataCategory;  

 @Column(name = "DataValue")  
 private boolean dataValue;
     public Date getDataType() {
    return dataType;
}

public void setDataType(Date dataType) {
    this.dataType = dataType;
}

JsonDateSerializer .java

package com.beingjavaguys.model;

import java.io.IOException;
import java.text.SimpleDateFormat;
import java.util.Date;
import org.codehaus.jackson.JsonGenerator;
import org.codehaus.jackson.JsonProcessingException;
import org.codehaus.jackson.map.JsonSerializer;
import org.codehaus.jackson.map.SerializerProvider;
import org.springframework.stereotype.Component;
/**
 * Used to serialize Java.util.Date, which is not a common JSON
 * type, so we have to create a custom serialize method;.
 *
 * @author Loiane Groner
 * http://loianegroner.com (English)
 * http://loiane.com (Portuguese)
 */
@Component
public class JsonDateSerializer extends JsonSerializer<Date>{
private static final SimpleDateFormat dateFormat = new SimpleDateFormat("MM-dd-yyyy");
@Override
public void serialize(Date date, JsonGenerator gen, SerializerProvider provider)
throws IOException, JsonProcessingException {
String formattedDate = dateFormat.format(date);
gen.writeString(formattedDate);
}
}

spring-config.xml

 <context:component-scan base-package="com.beingjavaguys.controller" />  
 <mvc:annotation-driven />  

 <bean id="dataSource"  
  class="org.springframework.jdbc.datasource.DriverManagerDataSource"> 
  <property name="driverClassName" value="com.microsoft.sqlserver.jdbc.SQLServerDriver" />  
  <property name="url" value="jdbc:sqlserver://localhost;database=Sample" />  
  <property name="username" value="sdsd" />  
  <property name="password" value="sdsd" /> 
    <property name="hibernate.dialect" value="com.beingjavaguys.model.SqlServerDialectWithNvarchar" /> 
 </bean>  


 <bean id="sessionFactory"  
 class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">  
 <property name="dataSource" ref="dataSource" />  
 <property name="annotatedClasses">  
 <list>  
   <value>com.beingjavaguys.model.Employee</value>   
      <value>com.beingjavaguys.model.DataValueTable</value> 
   </list>  
  </property>  
  <property name="hibernateProperties">  
   <props>  

    <prop key="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</prop>  
    <prop key="hibernate.show_sql">${hibernate.show_sql}</prop>  
   </props>  
  </property>  
 </bean>  


 <bean id="txManager"  
  class="org.springframework.orm.hibernate4.HibernateTransactionManager">  
  <property name="sessionFactory" ref="sessionFactory" />  
 </bean>  

 <bean id="persistenceExceptionTranslationPostProcessor"  
  class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" />  

 <bean id="dataDao" class="com.beingjavaguys.dao.DataDaoImpl"></bean>  
 <bean id="dataServices" class="com.beingjavaguys.services.DataServicesImpl"></bean>  
</beans>  

Right now i am getting response as "12312121000".I want it to display in 02-02-2015 format.Any suggestion and answers are welcomed.

Answer 1

With jackson you can annotate the entity such as

@JsonFormat(shape=JsonFormat.Shape.STRING, pattern="yyyy-MM-dd HH:mm:ss.000 ", timezone="UTC")
public Timestamp getDate() {
    return date;
}

This is an example of a test case I used to get back the timestamp in the pattern.

    ObjectMapper mapper = new ObjectMapper();
    JaxbAnnotationModule module = new JaxbAnnotationModule();
    mapper.registerModule(module);      
    mapper.setSerializationInclusion(Include.NON_NULL);
    // Object to JSON - entityBean I want to map to JSON
    String jsonOutput = mapper.writeValueAsString(entityBean);

Note. You must assign the annotated JsonFormat to getter method.