在Python中将以10为底的整数列表转换为以4为底的列表

Question

First of all I am sorry if the title did not correct. I am trying to build a program which convert a list of base 10 integer into its binary string.For example I have this list

a = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15]

and I want to convert it into base 4. Perhaps it should look like this

b4 = [[00],[01],[02],...[33]]

Below is what I've wrote so far

def base10base4(pix,b):
       pix = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15]
       for i in range(pix):
              digits = []
              while pix > 0:
                     digits.insert(0, pix % b)
                     pix = pix // b
print(base10base4(pix[i], 4))

When I run this code it give me error like this

NameError: name 'pix' is not defined

I am still very new in Python. Did I miss something or I need to change the whole code? I am using Python 3.5 Thank you for the help

Answer 1

This is a recursive function that returns a list of strings of base b representations of the integers in your list

def convertToBase(num,base):
    q=num/base
    r=num%base
    if (q == 0):
        return str(r)
    else:
        return convertToBase(q,base) + str(r)

pix = [0,3,15,56,12,34] #the list of numbers you want converted to base b
print [convertToBase(x,4) for x in pix]