json_decode使用不同的qoute返回null

Question

json_decode('["foo","bar"]', true) , this works, but this return NULL , json_decode("['foo','bar']", true) . The json_last_error() outputs 4 , JSON_ERROR_SYNTAX .

I've checked some answers from following questions;

json_decode() returns null issues

PHP json_decode() returns NULL with valid JSON?

json_decode returns NULL after webservice call

and tried following solutions but no success;

json_decode(str_replace('"', '"', "['foo','bar']"), true)

json_decode(stripslashes(str_replace('\\"', '"', "['foo','bar']")), true)

json_decode(stripslashes("['foo','bar']"), true)

json_decode(utf8_encode("['foo','bar']"), true)

I don't think it has to do with UTF-8 bom. Is it a PHP bug? Or how do I do turn "['foo','bar']" into '["foo","bar"]' as a workaround?

Answer 1

You are not providing valid json to a function. If u using javascript array

["foo","bar"]

You should use JSON.stringify to make JSON actually on js side.

Answer 2

JSON strings are quoted with double quotes " . Single quotes ' (which are common in PHP) are not valid JSON. No discussion. Thus, the input ['foo','bar'] is not valid json and json_decode correctly refuses to parse it .

Also see ECMA-404 , which defines the JSON format:

A string is a sequence of Unicode code points wrapped with quotation marks (U+0022). ¹

If you're looking for something to transform your JSON-ish string (where does it come from? Fix the source of the invalid JSON, preferably) into valid JSON; str_replace('\\'', '"', $jsonInput) should work in simple cases.

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¹ ( U+0022 is the double quote " )