PHP sqlite3-从准备好的语句中获取结果

Question

All the examples and documentation didnt really help or even offer an example for this so I m gonna ask here:

$db = new SQLite3(database.db);
$stmt = $db->prepare('SELECT COUNT(uid)  FROM kunden WHERE date = :date');
$stmt->bindValue(':ldate',$today,SQLITE3_TEXT);
$result =  $stmt->execute;

How can I get the result from that prepared statement? I know execute is not supposed to return a result. I tried using query and query_single but that didnt work. var_dump($result->fetchArray()); also didnt work. Help is much appreciated.

Answer 1

SQLite3Stmt::execute() is a function, and needs to be called as such:

$db = new SQLite3('database.db');
$stmt = $db->prepare('SELECT COUNT(uid)  FROM kunden WHERE date = :date');
$stmt->bindValue(':ldate',$today,SQLITE3_TEXT);
$result =  $stmt->execute();

You can then fetch the result like this:

$array = $result->fetchArray();
echo $array['COUNT(uid)'];