[英]Find index of a tuple in a list of tuples
I have a list of tuples and I want to find the index of a tuple if the tuple contains a variable.我有一个元组列表,如果元组包含一个变量,我想找到该元组的索引。 Here is a simple code of what I have so far:
这是我到目前为止的简单代码:
items = [('show_scllo1', '100'), ('show_scllo2', '200')]
s = 'show_scllo1'
indx = items.index([tupl for tupl in items if tupl[0] == s])
print(indx)
However I am getting the error:但是我收到错误:
indx = items.index([tupl for tupl in items if tupl[0] == s])
ValueError: list.index(x): x not in list
What I am doing wrong?我做错了什么?
The following will return you the indices of the tuples whose first item is s
以下将返回第一项为
s
的元组的索引
indices = [i for i, tupl in enumerate(items) if tupl[0] == s]
It seems as though you want the value, so you're asking for the index.好像您想要这个值,所以您要的是索引。
You can search the list for the next matching value, using next
:您可以使用
next
在列表中搜索下一个匹配值:
>>> items = [('show_scllo1', '100'), ('show_scllo2', '200')]
>>> next(number for (name, number) in items
... if name == 'show_scllo1')
'100'
So you don't really need the index at all.所以你根本不需要索引。
You are checking for the presence of a list
in items
, which doesn't contain a list
.您正在检查
items
中是否存在不包含list
的list
。 Instead, you should create a list
of each index where the item of interest is found:相反,您应该为找到感兴趣项目的每个索引创建一个
list
:
indx = [items.index(tupl) for tupl in items if tupl[0] == s]
index = next((i for i,v in enumerate(my_tuple_of_tuple) if v[0] == s),-1)
Is how you should probably do that你应该怎么做
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